Question

Given h(p)=p^2+2p, Solve h(p)=3

Answer 1

We have $h(p)=p^2+2p$ and $h(p)=3$ which means we can equate:

$p^2+2p=3$.

Subtract 3 from both sides:

$p^2+2p-3=0$.

Then solve for p:

$p^2+2p-3=0$.

$(p-1)(p+3)=0$.

So the product of two factors (p-1) and (p+3) is 0 which means at least one of the factors must be 0:

$p-1=0\implies p_1=1$.

Or

$p+3=0\implies p_2=-3$.

Hope this helps.