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diamong [38]
2 years ago
10

For each reaction, write the chemical formulae of the oxidized reactants in the space provided. Write the chemical formulae of t

he reduced reactants in the space provided. 2Fe(s) 3CuCl2(aq)
Chemistry
1 answer:
Annette [7]2 years ago
5 0

Answer : 'Fe' is oxidized reactant  and 'Cu' is reduced reactant.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

The balanced redox reaction will be:

2Fe(s)+3CuCl_2(aq)\rightarrow 2FeCl_3(aq)+3Cu(s)

In this reaction, the oxidation state of 'Fe' changes from (0) to (+3) that means 'Fe' lost 3 electron and it shows oxidation reaction and the oxidation state of 'Cu' changes from (+2) to (0) that means 'Cu' gain 2 electron and it shows reduction reaction.

Thus, 'Fe' is oxidized and 'Cu' is reduced.

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Reptile [31]

<u>Answer:</u> The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]

For the given chemical reaction:

C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]

We are given:

\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

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Answer:

The answer is all of the above

Explanation:

Sound has waves which are compression waves and those waves transfer into energy molecules. Sound is heard by human ears. Sound waves can behave in predictable ways. All sound requires a medium through to travel

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