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GrogVix [38]
2 years ago
5

A parent who is convinced that children have rights that ought not to be interfered with by adults is most likely:

Chemistry
1 answer:
DedPeter [7]2 years ago
7 0
(does this belong in chemistry?)


anyways, the parent was most likely a kid who wanted privacy. they wanted something so they are giving it to their kids.
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Determine the Density of a mass = 2000g and volume = 80ml
sergey [27]

Answer:

Explanation:

D = m/v

D = 2000/80 = 25

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2 years ago
if an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 mm in front of the len
Natasha2012 [34]
I think the answer is 7mm but I'm not sure.

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5 0
3 years ago
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Suppose you will fill a glass with ice cubes. When the ice cubes melt, is the glass still full
goblinko [34]
No. It will not still be full. The reason being is because when it melts, it's almost the same thing as compacting things down into another object (container). Therefore, you will have some room left i the glass. Like, if your trashcan was over-flowing, and you push it down to compact it so you can add more trash. So when the ice melts, it will not be full.
7 0
3 years ago
the pressure of a sample of argon gas was increased from 2.32 atm2.32 atm to 7.16 atm7.16 atm at constant temperature. if the fi
SOVA2 [1]

initial volume of the argon sample = 5.93L according to Boyle's law

What is Boyle's law ?

Boyle's law, also known as Mariotte's law, is a relationship describing how a gas will compress and expand at a constant temperature. The pressure (p) of a given quantity of gas changes inversely with its volume (v) at constant temperature, according to this empirical connection, which was established by the physicist Robert Boyle in 1662. In equation form, this means that pv = k, a constant.

According to Boyle's law

P1/V1 = P2/V2

P1 = initial pressure

P2 = final pressure

V1 =initial volume

V2= final volume

V1 = P1*V2/P2

V1 = 2.32*18.3/7.16 = 5.93L

initial volume of the argon sample = 5.93L according to Boyle's law

To know about Boyle's law from the link

brainly.com/question/26040104

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6 0
1 year ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reactionP4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°r
weqwewe [10]

Answer:

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

Explanation:

Enthalpy is denoted by H.

Enthalpy: Total heat change in a chemical reaction is called enthalpy.

The change of entalpy of a reaction is denoted by \bigtriangledown H^\circ_{rxn}

Hass's Law:The change in enthalpy of any process can be determined by calculating the sum of change in enthalpy of each of the steps involved in the process.

g= gas

S= solid

P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}=?

PCl₅(s)→ PCl₃(g)+Cl₂(g) .......(1)       \bigtriangledown H^\circ_{rxn}= +157KJ

P₄(g)+6Cl₂(g)→  4PCl₃(g).............(2)     \bigtriangledown H^\circ_{rxn}= -1207 KJ

If we flip a reaction the value of enthalpy will be change positive to negative or nagative to positive but the numerical value will be remain same.

We need rearrange the equation (1) because in the required equation Cl₂ is on the left side. So we flip the first equation.

PCl₃(g)+Cl₂(g)→PCl₅(s)......(3)          \bigtriangledown H^\circ_{rxn}= -157KJ

Multiplying 4 with equation (3)

4 PCl₃(g)+4Cl₂(g)→4PCl₅(s)......(4)          \bigtriangledown H^\circ_{rxn}=4×( -157)KJ= -628 KJ

Adding equation (2) and (4) we get

P₄(g)+6Cl₂(g)+4 PCl₃(g)+4Cl₂(g)→4PCl₃(g)+4PCl₅(s)    \bigtriangledown H^\circ_{rxn}=( -1207-628)KJ

⇒P₄(g)+10Cl₂(g)→4PCl₃(g)-4PCl₃(g)+4PCl₅(s)      \bigtriangledown H^\circ_{rxn}= - 1835KJ

⇒P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}= -1835 KJ

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

5 0
2 years ago
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