1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GrogVix [38]
3 years ago
5

A parent who is convinced that children have rights that ought not to be interfered with by adults is most likely:

Chemistry
1 answer:
DedPeter [7]3 years ago
7 0
(does this belong in chemistry?)


anyways, the parent was most likely a kid who wanted privacy. they wanted something so they are giving it to their kids.
You might be interested in
Which of the following represents an electron configuration that corresponds to the valence electrons of an element for which th
Mademuasel [1]

The electron configuration that corresponds to the valence electrons of an element for which there is an especially large jump between the second and third ionization energies is ns^2.

The valence electron configuration of an atom refers to the arrangement of electrons on the outermost shell of the atom.

Recall that a large jump in ionization energy occurs when electrons are removed from inner shells of the atom.

If we study our options closely, we will discover that option A has only two electrons in the valence shell (ns^2).

This means that the third ionization energy involves removing electrons from an inner shell which leads to large jump.

Learn more: brainly.com/question/14283892

6 0
3 years ago
Read 2 more answers
Part A. Two containers, one at 305 K and the other at 295 K, are placed in contact with each other. 1. 1 J of heat flows from th
posledela

Answer:

0.00011 JK.

The process does NOT violate the second law of thermodynamics

Explanation:

The following parameters are given which are going to help in solving for the change in entropy of the system. The term "entropy'' simply means the degree of disorderliness of a system.

=> The temperature of container A = 305 K, the temperature of container B = 295 K and the amount of heat generated when the containers are placed in contact with each other = 1. 1 J.

The change in entropy of the hot container = -(1/305) = - 0.00328 J/K.

The change in entropy of the cold container = 1/295 = 0.00339 J/K.

Therefore, the change in the entropy of the system = - 0.00328 J/K + 0.00339 J/K = 0.00011 JK.

Note that the change in entropy of the system gives a positive value. Hence, this process does not violate the second law of thermodynamics.

The process does NOT violate the second law of thermodynamics.

7 0
3 years ago
Is fire a solid liquid or gas?
Doss [256]
Fire is actually a chemical reaction. It's an oxidation reaction to be specific. When wood gets hot enough (the part of the wood that is burning) the large hydrocarbons break down to charred solids and a gas. The gas is what reacts with oxygen in the atmosphere to produced light, CO2 and H2O.
4 0
3 years ago
Read 2 more answers
A student wishes to calculate the experimental value of Ksp for AgI. S/he follows the procedure in Part 3 and finds Ecell to be
Ymorist [56]

Answer:

a)    [Ag+]dilute = 6.363  × 10⁻¹⁶ M  

b)    1.273 × 10⁻¹⁶

c)    2.629×10⁻¹⁹ M Thus; the value for  [Ag+ ]dilute will be too low

Explanation:

In an Ag | Ag+ concentration cell ,

The  anode reaction can be written as :

Ag ----> Ag+(dilute) + e-    &:

The  cathode reaction can be written as:

Ag+(concentrated) + e- ----> Ag

The  Overall Reaction : is

Ag+(concentrated) -----> Ag+(dilute)

However, the Standard Reduction potential of cell = E°cell = 0

( since both cathode and anode have same Ag+║Ag )

Also , given that the theoretical slope is - 0.0591 V

Therefore; the reduction potential of cell ; i.e

Ecell = E°cell - 0.0591 V × log ( [Ag+]dilute / [Ag+]concentrated )

0.839 V = 0 - 0.0591 V × log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) )  

log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) ) = - 14.1963  

[Ag+]dilute = \mathbf{10^{-14.1963} } × 1.0 × 10⁻¹ M

[Ag+]dilute = 6.363  × 10⁻¹⁶ M  

b)

AgI ----> Ag + (dilute) + I⁻

So , Solubility product = Ksp = [Ag⁺]dilute × [I⁻]  

= 6.363 × 10⁻¹⁶ M × 0.20 M  

= 1.273 × 10⁻¹⁶

c) If s/he mistakenly uses 1.039 V as Ecell; then the value for [Ag+]dilute will be :

Ecell = E°cell - 0.0591 V × log ( [Ag+]dilute / [Ag+]concentrated )

1.039 V = 0 - 0.0591 V × log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) )  

log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) ) = - 17.5804  

[Ag+]dilute = \mathbf{10^{-17.5804} } × 1.0 × 10⁻¹ M

[Ag+]dilute = 2.629×10⁻¹⁹ M

Thus, the value for  [Ag+ ]dilute will be too low

5 0
3 years ago
Two isotopes of the same element must have the same
emmainna [20.7K]

Answer:

atomic number

Explanation:

isotope is a family of an element with the same atomic number but different mass number.

3 0
2 years ago
Other questions:
  • Is it possible for the properties of a substance with a specific type of bond to vary
    8·1 answer
  • I need help ASAP!!! I need to know the model and the person who discovered it please!
    15·2 answers
  • Which indicator of a chemical change is shown?
    14·2 answers
  • Difference between water bath and incubator
    15·1 answer
  • Why radicals are highly reactive?
    12·1 answer
  • an object with a mass of 7.6 G raises the level of water in a graduated cylinder from 25.1 ml to 30.8 ml what is the density of
    5·1 answer
  • Deep, cold water is the __________. Warm, shallow water is the ___________.
    14·2 answers
  • Convert 25 kilograms to pounds.
    11·1 answer
  • What is the main reason for using a data table to collect data?
    13·1 answer
  • **BONUS** This Periodic Table was published several years ago. Which "new"
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!