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bonufazy [111]
3 years ago
8

Diatomic hydrogen gas and diatomic nitrogen gas react spontaneously to form a gaseous product. Give the balanced chemical equati

on (including phases) that describes this reaction

Chemistry
2 answers:
alex41 [277]3 years ago
5 0

Answer : NH_{3}

Explanation : When diatomic hydrogen gas and diatomic nitrogen gas reacts spontaneously it forms ammonia gas as the product.

we will have the following reactions; As all the reactants and products are in the gaseous state the subscript (g) is given to the molecules.

H_{2}_{(g)} + N_{2}_{(g)} ----> NH_{3}_{(g)}

But this is not a balanced equation, as on the right side of reactants we have 2 hydrogen atoms and 2 nitrogen atoms which gives the product which has one nitrogen and three hydrogen in the compound state.

So, balancing the equation, we get,

3H_{2}_{(g)} + N_{2}_{(g)} ----> 2NH_{3}_{(g)}

We multiplied 2 with the diatomic hydrogen molecule which resulted in production of 2 moles of ammonia as the product.

So, the complete balanced equation is;

3H_{2}_{(g)} + N_{2}_{(g)} ----> 2NH_{3}_{(g)}

iogann1982 [59]3 years ago
5 0

The balanced chemical equation (including phases) that describes the reaction between diatomic hydrogen gas and diatomic nitrogen gas:

\large{\boxed{\bold{3H_2(g)+N_2(g)\:\rightleftharpoons\:2NH_3(g)\:+heat}}}

<h3>Further explanation</h3>

Stochiometry in Chemistry learns about chemical reactions mainly emphasizing quantitative, such as calculations of volume, mass, number, which are related to the number of actions, molecules, elements, etc.

In chemical calculations, the reaction can be determined, the number of substances that can be expressed in units of mass, volume, mole, or determine a chemical formula, for example, the substance level or molecular formula of the hydrate.

The reaction equation is the chemical formula of reagents and product substances

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction equation there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

The reaction that happens between hydrogen and the nitrogen

H₂ (g) + N (g) ⇔NH3 (g) + heat

We balance the reaction coefficient by giving each compound a variable

aN₂ + bH₂ -> cNH₃

For example a = 1 then:

N: 2a -> c ---> 2 = c

H: 2b -> 3c ---> 2b = 3.2 ---> 2b = 6 -> b = 3

So

b = 3

c = 2

The equation becomes:

N₂ + 3H₂ -> 2NH₃

The process of making ammonia is known as the Haber-Bosch process. Hydrogen is obtained from the conversion of natural gas containing hydrocarbon compounds of propane or butane. This hydrogen is then reacted with nitrogen from free air to produce ammonia.

<h3>Learn more</h3>

The mass of one mole of raindrops

brainly.com/question/5233234

moles of NaOH

brainly.com/question/4283309

moles of water you can produce

brainly.com/question/1405182

Keywords: manufacture of ammonia, hydrogen, nitrogen

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Answer:

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Explanation:

Answer – Given, H_3PO_4 acid and there are three Ka values

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The transformation of H_2PO_4- (aq) to HPO_4^2-(aq)is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

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Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

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[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

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We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

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A substance X contains 10 gram of calcium carbonate calculate the number of mole of calcium carbonate present in X ​
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\LARGE{ \boxed{  \rm{ \red{Required \: answer}}}}

☃️ Chemical formulae ➝ \sf{CaCO_3}

<h3><u>How to find?</u></h3>

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

\boxed{ \sf{No. \: of \: moles =  \frac{given \: weight}{molecular \: weight} }}

<h3><u>Solution:</u></h3>

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O = 16

❍ Molecular weight of \sf{CaCO_3}

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Then, no. of moles,

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