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bonufazy [111]
3 years ago
8

Diatomic hydrogen gas and diatomic nitrogen gas react spontaneously to form a gaseous product. Give the balanced chemical equati

on (including phases) that describes this reaction

Chemistry
2 answers:
alex41 [277]3 years ago
5 0

Answer : NH_{3}

Explanation : When diatomic hydrogen gas and diatomic nitrogen gas reacts spontaneously it forms ammonia gas as the product.

we will have the following reactions; As all the reactants and products are in the gaseous state the subscript (g) is given to the molecules.

H_{2}_{(g)} + N_{2}_{(g)} ----> NH_{3}_{(g)}

But this is not a balanced equation, as on the right side of reactants we have 2 hydrogen atoms and 2 nitrogen atoms which gives the product which has one nitrogen and three hydrogen in the compound state.

So, balancing the equation, we get,

3H_{2}_{(g)} + N_{2}_{(g)} ----> 2NH_{3}_{(g)}

We multiplied 2 with the diatomic hydrogen molecule which resulted in production of 2 moles of ammonia as the product.

So, the complete balanced equation is;

3H_{2}_{(g)} + N_{2}_{(g)} ----> 2NH_{3}_{(g)}

iogann1982 [59]3 years ago
5 0

The balanced chemical equation (including phases) that describes the reaction between diatomic hydrogen gas and diatomic nitrogen gas:

\large{\boxed{\bold{3H_2(g)+N_2(g)\:\rightleftharpoons\:2NH_3(g)\:+heat}}}

<h3>Further explanation</h3>

Stochiometry in Chemistry learns about chemical reactions mainly emphasizing quantitative, such as calculations of volume, mass, number, which are related to the number of actions, molecules, elements, etc.

In chemical calculations, the reaction can be determined, the number of substances that can be expressed in units of mass, volume, mole, or determine a chemical formula, for example, the substance level or molecular formula of the hydrate.

The reaction equation is the chemical formula of reagents and product substances

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction equation there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

The reaction that happens between hydrogen and the nitrogen

H₂ (g) + N (g) ⇔NH3 (g) + heat

We balance the reaction coefficient by giving each compound a variable

aN₂ + bH₂ -> cNH₃

For example a = 1 then:

N: 2a -> c ---> 2 = c

H: 2b -> 3c ---> 2b = 3.2 ---> 2b = 6 -> b = 3

So

b = 3

c = 2

The equation becomes:

N₂ + 3H₂ -> 2NH₃

The process of making ammonia is known as the Haber-Bosch process. Hydrogen is obtained from the conversion of natural gas containing hydrocarbon compounds of propane or butane. This hydrogen is then reacted with nitrogen from free air to produce ammonia.

<h3>Learn more</h3>

The mass of one mole of raindrops

brainly.com/question/5233234

moles of NaOH

brainly.com/question/4283309

moles of water you can produce

brainly.com/question/1405182

Keywords: manufacture of ammonia, hydrogen, nitrogen

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Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol

\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)  

According to stoichiometry :

2 moles of SO_2 require = 1 mole of O_2

Thus 0.34 moles of SO_2 will require=\frac{1}{2}\times 0.34=0.17moles  of O_2

Thus SO_2 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

Moles of O_2 left = (0.68-0.17) mol = 0.51 mol

Mass of O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g

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Which of the following shows the 3 main jobs of a cell?
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What is the volume of 40.0 grams of argon gas at STP ?
MrRa [10]

Answer:

24.9 L Ar

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Aqueous Solutions</u>

  • States of Matter

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 40.0 g Ar

[Solve] L Ar

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of Ar - 39.95 g/mol

[STP] 22.4 L = 1 mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 40.0 \ g \ Ar(\frac{1 \ mol \ Ar}{39.95 \ g \ Ar})(\frac{22.4 \ L \ Ar}{1 \ mol \ Ar})
  2. [DA] Divide/Multiply [Cancel out units]:                                                         \displaystyle 24.9235 \ L \ Ar

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

24.9235 L Ar ≈ 24.9 L Ar

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