Answer:
0.56 liters
Explanation:
First we <u>convert 0.80 grams of O₂ into moles</u>, using its molar mass:
- 0.80 g ÷ 32 g/mol = 0.025 mol
At STP, 1 mol of any given mass occupies 22.4 L. With that information in mind we <u>calculate the volume that 0.025 moles of O₂ gas would occupy</u>:
- 0.025 mol * 22.4 L/mol = 0.56 L
Thus the answer is 0.56 liters.
Because you need to know how/ learn to try new things for (new experiments) and creativity will teach you different ways on how to do it.
Answer:
1. mixture
2. Homogenous
Explanation:
Copper II chloride is a compound because it consists of elements that are chemically combined together. When a solute in this case, copper II chloride is mixed with water- a solvent, the result is a homogenous mixture.
Homogenous substances are formed when a solute and a solvent combine, resulting in a mixture with uniform properties. Mixtures can be separated using relevant separation techniques.
Answer:
5.355 g
Explanation:
first you have 30.6 g from ammonium nitrate ( NH4NO3 )
molecular weight for NH4NO3 is 80 g/mole
and molecular weight for nitrogen gas N2 is 14 g/ mole
make this
NH4NO3 --------------> N2
80 g/mol --------------> 14 g/mol
30.6 g ---------------> x
So X = 14 x 30.6 ÷ 80 = 5.355 g of N2
Good Luck
One
Balance the Equation.
This has been done for you or it is given. Anyway this step is finished, but it must always be done.
Two
Find the molar mass of C6H12O6
6C = 6 * 12 = 72
12H = 12*1 = 12
CO = 6 * 16 = 96
Mol Mass = 180 grams / mol
Three
Find the mols of C6H12O6
n = ???
Molar Mass = 180 grams / mol
given mass = 13.2 grams.
n = given mass / molar mass
n = 13.2 / 180
n = 0.07333333 mols.
Four
Find the mols CO2
1 mol C6H12O6 will produce 6 mols CO2
0.0733333 mols will produce x
1/0.073333 = 6/x Cross multiply
x = 0.073333 * 6
x = 0.4399 moles.
Five
Find the volume given the conditions for temperature and pressure are STP conditions.
PV = nRT
R = 0.082057
n = 0.43999
P = 1 atmosphere
T = 0 + 273 = 273
V = ???
1 * V = 0.43999 * 082057 * 273
V = 10.2 L
Answer: B
Note if you give out Brainly awards I'd sure appreciate one. This was a lot of typing
