Given that Avogadro's number is 6.02 X 1023. Calculate the number of molecules present in 100.0moles of

Chemistry

1 answer:

GREYUIT [131]3 years ago

7 0

Answer: 6.02 x 10^25

Explanation:

In order to find the number of molecules you simply multiply the number of moles by 6.022 x 10^23.

1 mole is always equal to 6.022 x 10^23 no matter what element.

100.0 x 6.022 x 10^23 = 6.02 x 10^25

The answer only has three significant figures because 100.0 only has three.

You might be interested in

Density measurements were conducted on a 22.5oC sample of water which had a theoretical density of 0.997655 g/ml. A volume of 10

Sophie [7]

Let's divide the three experiments: The experiment with 10.00 mL of water is A), the experiment with 15.00 mL is B), and the experiment with 25.00 mL is C).

(1) Now let's calculate the experimental density of each experiment. Density (ρ) is equal to the mass divided by the volume, thus:

$p_{A} =9.98g/10.00mL=0.998g/mL\\p_{B} =15.61g/15.00mL=1.041g/mL\\p_{C} =25.65g/25.00mL=1.026g/mL$

(2)To calculate the average density, we add each density and divide the result by the number of experiments (in this case 3):

$p_{average}=\frac{p_{1}+p_{2}+p_{3}}{3} \\p_{average}=\frac{(0.998+1.041+1.026)g/mL}{3}\\p_{average}=1.022g/mL$

(3) The percent error is calculated by dividing the absolute value of the substraction of the theorethical and experimental values, by the theoretical value, times 100:

%error= $\frac{|p_{average}-p_{theoretical}|}{p_{theoretical}} *100$