Answer:
32000atm
Explanation:
Using Boyle's law equation;
P1V1 = P2V2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (
V2 = final volume (L)
According to the question below:
P1 = 160.0 atm
P2 = 3.0 atm
V1 = 600L
V2 = ?
Using P1V1 = P2V2
160 × 600 = 3 × V2
96000 = 3V2
V2 = 96000/3
V2 = 32000atm
Answer:
2445 L
Explanation:
Given:
Pressure = 1.60 atm
Temperature = 298 K
Volume = ?
n = 160 mol
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 08206 L.atm/K.mol
Applying the equation as:
1.60 atm × V = 160 mol × 0.08206 L.atm/K.mol × 298 K
<u>⇒V = 2445.39 L</u>
Answer to four significant digits, Volume = 2445 L
Iodine electron configuration is:
1S^2 2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 5S^2 4d^10 5P^5
when Krypton is the noble gas in the row above iodine in the periodic table,
we can change 1S^2 2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 by the symbol
[Kr] of Krypton.
So we can write the electron configuration of Iodine:
[Kr] 5S^2 4d^10 5P^5
Answer:
A is your answer..... !!!!!!!!!!!!!
