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ohaa [14]
3 years ago
13

Greatest common factor for 40,10

Mathematics
2 answers:
horrorfan [7]3 years ago
8 0
The greatest common factor of 40&10 is 10
Marrrta [24]3 years ago
7 0
Answer 40 if wrong tell me I might be
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Equivalent expressions for 7x-6x+4x
Alekssandra [29.7K]

Answer:

<h3>5x</h3>

Step-by-step explanation:

7x-6x+4x ← <em>(Add and subtract elements to the numbers from left to right.)</em>

<em />

7-6+4

PEMDAS- (Parenthesis, Exponents, Multiply, Divide, Add, and Subtract) from left to right.

7-6+4 ← (Add & subtract.)

7-6=1

1+4=5

= 5x

5x, which is our answer.

5 0
3 years ago
WILL GIVE BRAINLIEST!<br> What’s the perimeter and area of this figure?
yulyashka [42]

Perimeter is 7y+2

Area is 4y^2+1y

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3 years ago
How do you do 5+5?
steposvetlana [31]

Answer:

If you had 5 apples and Johnny gave you five more how much do you have? Lets count

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6 0
3 years ago
If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers. Roun
AlekseyPX

Answer:

P = 0.008908

Step-by-step explanation:

The complete question is:

The table below describes the smoking habits of a group of asthma sufferers

               Nonsmokers      Light Smoker     Heavy smoker      Total

Men                        303                     35                           37        375

Women                   413                     31                            45        489

Total                        716                     66                           82        864

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers.

The number of ways in which we can select x subjects from a group of n subject is given by the combination and it is calculated as:

nCx=\frac{n!}{x!(n-x)!}

Now, there are 82C2 ways to select subjects that are both heavy smokers. Because we are going to select 2 subjects from a group of 82 heavy smokers. So, it is calculated as:

82C2=\frac{82!}{2!(82-2)!}=3321

At the same way, there are 864C2 ways to select 2 different people from the 864 subjects. It is equal to:

864C2=\frac{864!}{2!(864-2)!}=372816

Then, the probability P that two different people from the 864 subjects are both heavy smokers is:

P=\frac{82C2}{864C2}=\frac{3321}{372816}=0.008908

4 0
3 years ago
Please look at a the attached image below, it’s urgent
sveta [45]

Answer:

40⁰ is angle boc

Aod is 75⁰ hope it's help yo

4 0
2 years ago
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