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ohaa [14]
3 years ago
13

Greatest common factor for 40,10

Mathematics
2 answers:
horrorfan [7]3 years ago
8 0
The greatest common factor of 40&10 is 10
Marrrta [24]3 years ago
7 0
Answer 40 if wrong tell me I might be
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If f(a)=(a•a•a)-(a•a) + a-1 what is the value of f(-3)?
Elena L [17]

Answer:

-40

Step-by-step explanation:

f(a) = a³ - a² + a - 1

f(-3) = (-3)³ - (-3)² + (-3) - 1

f(-3) = (-27) - (9) + (-3) -1

f(-3) = -27 - 9 -3 - 1

f(-3) = -40

3 0
3 years ago
Solve for m:<br> 2r= m/r <br><br><br> m = 2r<br> m = 2r squared by 2<br> m=r<br> m = 2
Bad White [126]
Solution

Switch sides so that m is on the left side

m/r = 2r

Them multiply both sides by r

mr/r = 2rr

Now simplify the equation

m = 2r^2

Therefore the equation evaluates to
m = 2r squared by 2
6 0
2 years ago
The number of tickets purchased by an individual for Beckham College's holiday music festival is a uniformly distributed random
Zanzabum

1) Mean: 6.5

2) Standard deviation: 3.2

Step-by-step explanation:

1)

A uniform random distribution is the distribution of a variable that can assume n different values, and each of these values is equally likely to occur.

This means that the probability of occurring of each of these values is the same:

p(x_1)=p(x_2)=...=p(x_n)

For a uniform random distribution, the mean of the distribution is simply equal to the median value of the distribution, which is exactly at the center of the distribution itself. It can be calculated as

\bar x = \frac{1}{2}(a+b)

where

a is the lowest value of the distribution

b is the highest value of the distribution

Here the distribution consists of all values ranging from 1 to 12, so:

a = 1

b = 12

Therefore the mean value is

\bar x=\frac{1}{2}(1+12)=6.5

2)

For a uniform random distribution, it can be dimostrated that the variance of the distribution is

\sigma^2 = \frac{1}{12}(b-a)^2

For the distribution in this problem, we have:

a = 1

b = 12

Therefore the variance is

\sigma^2 = \frac{1}{12}(12-1)^2=10.08

The standard deviation is the square root of the variance, therefore for this distribution it is:

\sqrt{\sigma^2}=\sqrt{10.08}=3.2

Learn more about mean and standard deviation:

brainly.com/question/6073431

brainly.com/question/8799684

brainly.com/question/4625002

#LearnwithBrainly

3 0
3 years ago
Don Price bought a house for $70,000. He rents the house for $900 per month. He has $700 in monthly expenses.
frutty [35]
Annual rent=$10,800
Annual Expenses=$8,400
Rate of income=moneyt
3 0
3 years ago
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Juli2301 [7.4K]

Answer: what’s the answer ?

Step-by-step explanation:

5 0
3 years ago
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