You can easily see that

In fact, you have

This kind of transformation, where you add a constant to change

result in a vertical translation, k units up if
, k units down if 
So, in this case, the graphs of f(x) and g(x) have the same shape, and they are vertically shifted 5 units apart, g(x) is higher and f(x) is lower.
Answer:
(2, 4)
Step-by-step explanation:
To solve this system, the easiest way would be to use the substitution method. You can simply plug in, or substitute the value of y from the second equation, which is -x + 6, into the first equation. So you would get:
-x + 6 = 3x - 2
6 = 4x - 2
8 = 4x
2 = x.
To find y, just substitute the value of x, which is 2, into either equation:
y = 3(2) - 2
y = 6 -2
y = 4.
Make sure you write your answer as an ordered pair! So, the final answer is (2, 4). Hope that helped! :)
Answer:
a=35 given
b=40
c=110
I couldn't complete see c. Please look at the picture to see what I assumed it to be.
Step-by-step explanation:
Hmmm... I guess a and b are not vertical.
We are given b=180-4a and a=35 so b=180-4(35)=180-140=40.
So b=40.
Isosceles triangles always have congruent base angles. So let's call both of the base angles in the bottom triangle x.
That means x+x+40=180.
We need to solve this for x.
Combine like terms:
2x+40=180
Subtract 40 on both sides:
2x=140
Divide both sides by 2:
x=140/2
Simplify:
x=70
So I'm assuming that c and it's adjacent angle are sitting on a straightedge together which means 70+c=180.
70+c=180
Subtract 70 on both sides:
c=180-70
Simplify:
c=110
Answer:
<h3>(A)</h3>
The answers will have the same value, beacuse both scientific notations have the same coefficient, 4.2 and 1.4. Also, if you mentally subtract the exponents of those powers, you would have the same exponent. So, equal coefficient and equal exponent will give the same result.
<h3>(B)</h3>
The value of each expression can be found by dividing coefficients and powers.

<h3>(C)</h3>
The value of each expression in standard form is

Remember that standard form refers to the number without the ten-power.