The domain of a function is the x and the range of a function is the y.
When a question asks you to find the domain of a function or the range of a given function, you have to find all the possible x values if domain and all the possible y values if range.
Area of a circle for (360degrees) = pi*(r^2)
Area of part of a circle with angle θ=(θ/360)*(pi*)*(r^2)
<span>(θ/360)*pi*(6^2)=12*pi
</span>solving, <span>θ=(12/36)*360
</span><span>θ=120 degress
</span>
Answer:
6
Step-by-step explanation:
3 + 3 = 6
![\bf f(x)=x+\cfrac{1}{x}\qquad \left[\frac{1}{2},2 \right]\\\\ -----------------------------\\\\ \cfrac{df}{dx}=1+\left(-1x^{-2} \right)\implies \cfrac{df}{dx}=1-\cfrac{1}{x^2} \\\\\\ f'(c)=1-\cfrac{1}{c^2}\quad \quad 1-\cfrac{1}{c^2}=\cfrac{f(2)-f\left( \frac{1}{2} \right)}{2-\frac{1}{2}} \\\\\\ 1-\cfrac{1}{c^2}=\cfrac{\frac{5}{2}-\frac{5}{2}}{\frac{3}{2}}\implies 1-\cfrac{1}{c^2}=\cfrac{0}{\frac{3}{2}}\implies 1-\cfrac{1}{c^2}=0 \\\\\\ 1=\cfrac{1}{c^2}\implies c^2=1\implies c=\pm\sqrt{1}\implies c=\pm 1](https://tex.z-dn.net/?f=%5Cbf%20f%28x%29%3Dx%2B%5Ccfrac%7B1%7D%7Bx%7D%5Cqquad%20%5Cleft%5B%5Cfrac%7B1%7D%7B2%7D%2C2%20%20%5Cright%5D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%5Ccfrac%7Bdf%7D%7Bdx%7D%3D1%2B%5Cleft%28-1x%5E%7B-2%7D%20%20%5Cright%29%5Cimplies%20%5Ccfrac%7Bdf%7D%7Bdx%7D%3D1-%5Ccfrac%7B1%7D%7Bx%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Af%27%28c%29%3D1-%5Ccfrac%7B1%7D%7Bc%5E2%7D%5Cquad%20%5Cquad%201-%5Ccfrac%7B1%7D%7Bc%5E2%7D%3D%5Ccfrac%7Bf%282%29-f%5Cleft%28%20%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%7D%7B2-%5Cfrac%7B1%7D%7B2%7D%7D%0A%5C%5C%5C%5C%5C%5C%0A1-%5Ccfrac%7B1%7D%7Bc%5E2%7D%3D%5Ccfrac%7B%5Cfrac%7B5%7D%7B2%7D-%5Cfrac%7B5%7D%7B2%7D%7D%7B%5Cfrac%7B3%7D%7B2%7D%7D%5Cimplies%201-%5Ccfrac%7B1%7D%7Bc%5E2%7D%3D%5Ccfrac%7B0%7D%7B%5Cfrac%7B3%7D%7B2%7D%7D%5Cimplies%201-%5Ccfrac%7B1%7D%7Bc%5E2%7D%3D0%0A%5C%5C%5C%5C%5C%5C%0A1%3D%5Ccfrac%7B1%7D%7Bc%5E2%7D%5Cimplies%20c%5E2%3D1%5Cimplies%20c%3D%5Cpm%5Csqrt%7B1%7D%5Cimplies%20c%3D%5Cpm%201)
there's a quick graph below of the bounds and the tangent at "c"
not happening -2 or 2 will have a tangent parallel to a,b, needless to say -2 is out of the range [a,b] anyway, so the only value is really 1, on the positive 1st quadrant
