Answer:
Corect answer is D
Explanation:
Assuming that the C
O
2 gas is behaving ideally, therefore, we can use the ideal gas law to find the pressure increase in the container by:
P
V=nRT ⇒ P=n
R
T
/V
n=no of moles of the gas = mass/molar mass
Molar mass o f C
O
2=44g/mol, mass = 44g
mole n = 1mole
T=20C=293K
R=0.0821L.atm/mol.K
P=nRT/V
P = 1 x 0.0821 x 293/2
P = 12atm
The finished product or waste that forms as a result of a process is output.
Answer:
Technician A
Explanation:
If Technician B was correct, and the master cylinder is defective - then no braking action would occur.
This is not true however, as some breaking action eventually occurs, meaning it must be out of adjustment.
Answer:
1.59 seconds
12.3 meters
but if you are wise you will read the entire answer.
Explanation:
This is a good question -- if not a bit unusual. You should try and understand the details. It will come in handy.
Time
<u>Given</u>
a = 0 This is the critical point. There is no horizontal acceleration.
d = 20 m
v = 12.6 m/s
<u>Formula</u>
d = vi * t + 1/2at^2
<u>Solution</u>
Since the acceleration is 0, the formula reduces to
d = vi * t
20 = 12.6 * t
t = 20 / 12.6
t = 1.59 seconds.
It takes 1.59 seconds to hit the ground
Height of the building
<u>Givens</u>
t = 1.59 sec
vi = 0 Another critical point. The beginning speed vertically is 0
a = 9.8 m/s^2 The acceleration is vertical.
<u>Formula</u>
d = vi*t + 1/2 a t^2
<u>Solution</u>
d = 1/2 a*t^2
d = 1/2 * 9.8 * 1.59^2
d = 12.3 meters.
The two vi's are not to be confused. The horizontal vi is a number other other 0 (in this case 12.6 m/s horizontally)
The other vi is a vertical speed. It is 0.
Answer
The dedicated graphics card is used when performing hardware-intensive tasks so as to ensure efficiency and balanced performance. However, it uses more power and thus produces more heat. When the cooling system is not sufficient or the room is not well ventilated, your PC begins to overheat while playing games. Explanation: How does the second law of thermodynamics relate to the direction of heat flow? Heat of itself never flows from a cold object to a hot object. ... The second law expresses the maximum efficiency of a heat engine in terms of hot and cold temperatures. one of these answers i am not sure