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uysha [10]
3 years ago
7

What happens if the air pressure in your throat and outside body is less than the air pressure in your middle ear when you swall

ow
Physics
1 answer:
andrezito [222]3 years ago
8 0

Answer:

When the air pressure in the throat and outside the body is less than the air pressure in the middle ear, barotrauma occurs.

Explanation:

Ear barotrauma is a medical condition that describes discomfort in the ear which is caused by pressure differences in the inner and outer ear drum.

Usually, the air pressure in the middle ear is the same as the air pressure in the throat and outside the body.

When we swallow, the eustachian tube opens up and air flows out of and into the middle ear, this balances the pressure. But if the eustachian tube is blocked, the air pressure in the throat and outer body become different from the air pressure in the middle ear.

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QUESTION 3 ( MARKS]
horrorfan [7]

Answer:

392 N

Explanation:

Draw a free body diagram of the rod.  There are four forces acting on the rod:

At the wall, you have horizontal and vertical reaction forces, Rx and Ry.

At the other end of the rod (point X), you have the weight of the sign pointing down, mg.

Also at point X, you have the tension in the wire, T, pulling at an angle θ from the -x axis.

Sum of the moments at the wall:

∑τ = Iα

(T sin θ) L − (mg) L = 0

T sin θ − mg = 0

T = mg / sin θ

Given m = 20 kg and θ = 30.0°:

T = (20 kg) (9.8 m/s²) / (sin 30.0°)

T = 392 N

7 0
3 years ago
When you rub your hands together, you cannot push harder on one hand than the other. can push harder on one hand than the other.
Sholpan [36]
I think it means that your putting in an equal amount of force on each hand because it's the same brain that controls what you do. I think that's what it means, not entirely sure but hope this helps
3 0
3 years ago
A string of 18 identical holiday tree lights is connected inseries to a 190V source. The string dissipates 62.0 W. One of thebul
PtichkaEL [24]

Answer:

549.9 ohms, 65.65 watts, the power went up

Explanation:  power P = V²/R

v= 190volts , P =62watts

from P =V²/R

62=190²/R

making R the subject

R×62= 190²

62R =36100

R=36100/62

R=586.25 ohms

Resistance of each lamp = 586.26/18 =32.3ohms

a) resistance of the light string now = 17×32.3 = 549.9 ohms

b) P=V²/R

where R=549.9ohms , P=?

P=190²/549.9

P=36100/549.9

P=65.65watts

Power dissipated has increased( went up )

7 0
3 years ago
Why do the asbestos roof of house get lifted in hurricane ?
kirill115 [55]
Sometimes bc of how strong the wind can be
5 0
3 years ago
A pair of parallel plates, forming a capacitor, are charged. The plates are pulled apart to double the original separation, the
polet [3.4K]

Answer:

The final energy will be halved of the original energy.

Explanation:

As we know that the capacitance,

C = εA/d

C = capacitance

A = area of plate

d = distance or separation between the plates

ε = permitivity of dielectric material

As you can see from the formula that the capacitance ( ability of the capacitor to store charge) is inversaly proportional to the separation of the plates. If all the other factors kept constant then increasing the distance between the plates will decrease the ability of the capacitor to store energy. So we can say that by doubling the separation, the capacitance or energy stored will become half.

4 0
3 years ago
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