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n200080 [17]
3 years ago
12

You pull with a force of 77 N on a piece of luggage of mass 23 kg, but it does

Physics
2 answers:
Sergio [31]3 years ago
7 0

Answer:

184N

Explanation:

Frictional force is defined as a force of opposition. This force opposes the moving force. The body placed on a plane surface has a frictional force proportional to the normal reaction force acting on the body.

Mathematically, Ff = nR where;

Ff is the frictional force

n is the coefficient of static friction between the luggage and the floor.

R is the normal reaction which is equal to the weight (W) of the body.

W = mg

Weight = 23×10 = 230N

Since weight = normal reaction

Normal reaction = 230N

coefficient of friction between the luggage and the floor = 0.8

Frictional force (Ff) = 0.8×230

Frictional force = 184N

Therefore, the force of static friction acting on the luggage is 184N

Vinvika [58]3 years ago
5 0

Answer:

The force of static friction acting on the luggage is, Fₓ = 180.32 N

Explanation:

Given data,

The mass of the luggage, m = 23 kg

You pulled the luggage with a force of, F = 77 N

The coefficient of static friction of luggage and floor, μₓ = 0.8

The formula for static frictional force is,

                                      Fₓ = μₓ · η

Where,

                                  η - normal force acting on the luggage 'mg'

Substituting the values in the above equation,

                                   Fₓ = 0.8 x 23 x 9.8

                                        = 180.32 N

Hence, the minimum force require to pull the luggage is, Fₓ = 180.32 N

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(a)Equation of minima = sinθ  = mλ/α

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(b) Find the closest minima for green

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Learn more about the Diffraction with the help of the given link:

brainly.com/question/12290582

#SPJ4

I understand that the question you are looking for is "Two lasers, one red (with wavelength 633.0 nm) and the other green (with wavelength 532.0 nm), are mounted behind a 0.150-mm slit. On the ot

Question

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