All categories

4 years ago

You pull with a force of 77 N on a piece of luggage of mass 23 kg, but it does

Physics

2 answers:

Sergio [31]4 years ago

7 0

Answer:

184N

Explanation:

Frictional force is defined as a force of opposition. This force opposes the moving force. The body placed on a plane surface has a frictional force proportional to the normal reaction force acting on the body.

Mathematically, Ff = nR where;

Ff is the frictional force

n is the coefficient of static friction between the luggage and the floor.

R is the normal reaction which is equal to the weight (W) of the body.

W = mg

Weight = 23×10 = 230N

Since weight = normal reaction

Normal reaction = 230N

coefficient of friction between the luggage and the floor = 0.8

Frictional force (Ff) = 0.8×230

Frictional force = 184N

Therefore, the force of static friction acting on the luggage is 184N

Vinvika [58]4 years ago

5 0

Answer:

The force of static friction acting on the luggage is, Fₓ = 180.32 N

Explanation:

Given data,

The mass of the luggage, m = 23 kg

You pulled the luggage with a force of, F = 77 N

The coefficient of static friction of luggage and floor, μₓ = 0.8

The formula for static frictional force is,

Fₓ = μₓ · η

Where,

η - normal force acting on the luggage 'mg'

Substituting the values in the above equation,

Fₓ = 0.8 x 23 x 9.8

= 180.32 N

Hence, the minimum force require to pull the luggage is, Fₓ = 180.32 N

You might be interested in

Starting from rest, a solid sphere rolls without slipping down an incline plane. At the bottom of the incline, what does the ang

Marrrta [24]

Answer:

2/R*sqrt (g*s*sin(θ)) = w

Explanation:

Assume:

- The cylinder with mass m

- The radius of cylinder R

- Distance traveled down the slope is s

- The angular speed at bottom of slope w

- The slope of the plane θ

- Frictionless surface.

Solution:

- Using energy principle at top and bottom of the slope. The exchange of gravitational potential energy at height h, and kinetic energy at the bottom of slope.

ΔPE = ΔKE

- The change in gravitational potential energy is given as m*g*h.

- The kinetic energy of the cylinder at the bottom is given as rotational motion: 0.5*I*w^2

- Where I is the moment of inertia of the cylinder I = 0.5*m*R^2

We have:

m*g*s*sin(θ) = 0.25*m*R^2*w^2

2/R*sqrt (g*s*sin(θ)) = w

- The angular velocity depends on plane geometry θ , distance travelled down slope s, Radius of the cylinder R , and gravitational acceleration g

3 0

3 years ago

Light travels at 300,000,000 m/s. This is an example

mafiozo [28]

Answer:

ook soooooo

Explanation:

3 0

3 years ago

How many items are present in the compound (NH4)2Cr2O7

SVEN [57.7K]

In 2Cr2O7 there’s 2 items; Cr and O

5 0

3 years ago

the total positive charge is QQQ = 1.62×10−6 CC , what is the magnitude of the electric field caused by this charge at point P,

balu736 [363]

Answer:

6.1 × 10^9 Nm-1

Explanation:

The electric field is given by

E= Kq/d^2

Where;

K= Coulombs constant = 9.0 × 10^9 C

q = magnitude of charge = 1.62×10−6 C

d = distance of separation = 1.53 mm = 1.55 × 10^-3 m

E= 9.0 × 10^9 × 1.62×10−6/(1.55 × 10^-3 )^2

E= 14.58 × 10^3/2.4 × 10^-6

E= 6.1 × 10^9 Nm-1

8 0

3 years ago

Moving with a speed of v km/hour, a train travels the distance between the points A and B, which is 600 km, in t hours. Find the

NARA [144]

<h2>Formula which describes v in terms of t is $v=\frac{600}{t}km/hr$ </h2>

Explanation:

A train travels the distance between the points A and B, which is 600 km

Distance between A and B = 600 km

Speed of train = v

Time taken by train = t

We know that

Distance traveled = Speed of travel x Time taken

600 = v x t

$v=\frac{600}{t}km/hr$

Formula which describes v in terms of t is $v=\frac{600}{t}km/hr$

3 0

3 years ago