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3 years ago

You pull with a force of 77 N on a piece of luggage of mass 23 kg, but it does

Physics

2 answers:

Sergio [31]3 years ago

7 0

Answer:

184N

Explanation:

Frictional force is defined as a force of opposition. This force opposes the moving force. The body placed on a plane surface has a frictional force proportional to the normal reaction force acting on the body.

Mathematically, Ff = nR where;

Ff is the frictional force

n is the coefficient of static friction between the luggage and the floor.

R is the normal reaction which is equal to the weight (W) of the body.

W = mg

Weight = 23×10 = 230N

Since weight = normal reaction

Normal reaction = 230N

coefficient of friction between the luggage and the floor = 0.8

Frictional force (Ff) = 0.8×230

Frictional force = 184N

Therefore, the force of static friction acting on the luggage is 184N

Vinvika [58]3 years ago

5 0

Answer:

The force of static friction acting on the luggage is, Fₓ = 180.32 N

Explanation:

Given data,

The mass of the luggage, m = 23 kg

You pulled the luggage with a force of, F = 77 N

The coefficient of static friction of luggage and floor, μₓ = 0.8

The formula for static frictional force is,

Fₓ = μₓ · η

Where,

η - normal force acting on the luggage 'mg'

Substituting the values in the above equation,

Fₓ = 0.8 x 23 x 9.8

= 180.32 N

Hence, the minimum force require to pull the luggage is, Fₓ = 180.32 N

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Even in the most advanced circuits, we cannot oscillate electrons back and forth at that rate through wires. But we can oscillat

den301095 [7]

Answer:

the oscillations of the electrons must be in the 10⁸ Hz = 100 MHz range

Explanation:

The speed of a wave of radio, television, light, heat, all are manifestations of electromagnetic waves that are oscillations of electric and magnetic fields that support each other, the speed of all these waves is the same and the vacuum is equal to c = 3 108 m / s

All waves have a relationship between the speed of the wave, its frequency and wavelength

c = λ f

f = c /λ

for this case lam = 1 m

f = 3 10⁸/1

f = 3 10⁸ Hz

the oscillations of the electrons must be in the MHz range

It should be clarified that the speed of light in air is a little lower

n = c / v

v = c / n

the refractive index of vacuum is n = 1 and the refractive index of air is n = 1.000002

5 0

3 years ago

A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical

iris [78.8K]

Answer:

17.71N/m

Explanation:

The period of the spring is expressed according to the expression;

$T = 2 \pi \sqrt{\frac{m}{k} } \\$

m is the mass of the object

k is the force constant

Given

m = 5.50kg

T = 3.50s

Substitute into the formula;

$T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} = \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k = 17.71N/m$