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Alexeev081 [22]
3 years ago
7

Omar is born weighing 8 pounds, 3 ounces. The doctor says he should gain about 5 ounces each week for the next 4 weeks. How much

should Omar weigh after 4 weeks?
Mathematics
2 answers:
satela [25.4K]3 years ago
8 0

20

Step-by-step explanation:

5x4

anzhelika [568]3 years ago
6 0

Omar will be 9 pounds and 7 ounces

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Gareth 30 students in a class and the ratio of boys to girls in the class is 2:3 calculate the number of goals
pishuonlain [190]

Answer:

<em>There are 12 boys and 18 girls</em>

Step-by-step explanation:

<u>Equations</u>

There are 30 students in a class. Let's call:

x = number of boys

Since the sum of boys and girls is 30:

30 - x = number of girls

The ratio of boys to girls is 2:3, thus:

\displaystyle \frac{x}{30-x}=\frac{2}{3}

Crossing denominators:

3x = 2(30 - x)

Operating the parentheses:

3x = 60 - 2x

Adding 2x:

5x = 60

Dividing by 5:

x = 60/5 = 12

x = 12

There are 12 boys and 30-12=18 girls

8 0
3 years ago
Solve the system of equations using the addition method.
stepladder [879]

Answer:

A) 5x - 2y = 12

B) 3x + 2y = 36  Adding both equations eliminates "y"

8x = 48

x = 6   Putting x=6 into equation B we get

3*6 + 2y = 36

2y = 18

y = 9

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.​
Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is \dfrac{15}{2}.

To find:

The sum of first six terms.​

Solution:

We have,

S_2=6

S_4=\dfrac{15}{2}

Sum of first n terms of a GP is

S_n=\dfrac{a(1-r^n)}{1-r}              ...(i)

Putting n=2, we get

S_2=\dfrac{a(1-r^2)}{1-r}

6=\dfrac{a(1-r)(1+r)}{1-r}

6=a(1+r)                    ...(ii)

Putting n=4, we get

S_4=\dfrac{a(1-r^4)}{1-r}

\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}

\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}

\dfrac{15}{2}=6(1+r^2)            (Using (ii))

Divide both sides by 6.

\dfrac{15}{12}=(1+r^2)

\dfrac{5}{4}-1=r^2

\dfrac{5-4}{4}=r^2

\dfrac{1}{4}=r^2

Taking square root on both sides, we get

\pm \sqrt{\dfrac{1}{4}}=r

\pm \dfrac{1}{2}=r

\pm 0.5=r

Case 1: If r is positive, then using (ii) we get

6=a(1+0.5)  

6=a(1.5)  

\dfrac{6}{1.5}=a  

4=a

The sum of first 6 terms is

S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}

S_6=\dfrac{4(1-0.015625)}{0.5}

S_6=8(0.984375)

S_6=7.875

Case 2: If r is negative, then using (ii) we get

6=a(1-0.5)  

6=a(0.5)  

\dfrac{6}{0.5}=a  

12=a  

The sum of first 6 terms is

S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}

S_6=\dfrac{12(1-0.015625)}{1.5}

S_6=8(0.984375)

S_6=7.875

Therefore, the sum of the first six terms is 7.875.

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2 years ago
Convert this radical form to exponential form.
Elden [556K]

Answer:

I think it's 7.93725

I'm not sure if I did this correctly

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3 years ago
Round your answer to this problem to the nearest degree.
Vika [28.1K]
Use the sine law: sinB/b = sinA/a

SinB = b*sinA/a

sinB = 3*sin120° /8

∠ B = 18.94° ≈ 19°
5 0
3 years ago
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