Question

)consider two positively charged particles, one of charge q0 (particle 0) fixed at the origin, and another of charge q1 (particle 1) fixed on the y-axis at (0,d1,0). what is the net force f⃗ on particle 0 due to particle 1?

Answer 1

here force between two particles is given by Coulomb's law where two particles will either repel or attract each other

this force of attraction or repulsion is given by the equation

$F = \frac{kq_1 q_2}{r^2}$

here we know that

$q_1 , q_2$ = two point charges

r = distance between two charges

so now we will substitute all values in it

$F = \frac{kq_0q_1}{d_1^2}$

so above is the force between two point charges