Answer:
Explanation:
We can find out the velocity of pinball after being fired from the equation of conservation of mechanical energy
1/2 m v² = 1/2 k x² , m is mass of ball , v is velocity after firing , k is spring constant , x is depression in spring.
.1 x v² = 40 x .1 x .1
v = 2 m /s
ball of mass .1 , collides with velocity 2 m /s ,
from the equation of elastic collision
v₂ = (m₂ - m₁) u₁ / (m₂ + m₁) + 2m₁m₂u₂ / (m₂ + m₁)
m₁ ,u₁ are mass and velocity of first ball , m₂ , u₂ are mass and velocity of second mass , v₂ is velocity of second mass after collision.
u₁ = 2 , u₂ = 0 , m₁ = .1 m₂ = .3
v₂ = (.3 - .1 ) x 2/ (.3 + .1 )
= (.2 / .4 )x 2
= 1 m /s
So .3 kg ball will move with velocity of 1 m /s in the same direction as .1 m mass collided with it.
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