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qwelly [4]
3 years ago
8

What environmental condition is most likely to trigger the closing of leaf stoma? Wind, heat, darkness, or lack of moisture

Chemistry
2 answers:
erma4kov [3.2K]3 years ago
8 0
Lack of moisture :)               

Over [174]3 years ago
4 0

Answer:

The correct answer is " lack of moisture".

Explanation:

The opening or closing of the stomata is regulated in the plant by environmental factors such as light and water availability. In cases of lack of humidity, the stomas are closed preventing water losses in the plant. This also prevents the exchange of gases and the entry of atmospheric carbon dioxide necessary for plant nutrition through the process of photosynthesis.

Have a nice day!

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Name each of the following organic molecules. 
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A. 2-Fluoro-3-Chlorohexane
B. 1-Bromo-2-Chloro-3-Fluorocyclopentane
C. 4-ethyl-5-methylhexane
D. 2,4,5-trimethylheptane
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2 years ago
Real life example of when temperature increases, then the pressure increases.
timurjin [86]

Answer:

Tyre

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2 years ago
How does the muscular system work with the respiratory system?
djverab [1.8K]

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Explanation:

6 0
3 years ago
What is the name of the binary compound that has the formula k2s?
kozerog [31]

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8 0
2 years ago
A tetraphenyl phosphonium chloride (TPPCl) powder (FW=342.39) is 94.0 percent pure. How many grams are needed to prepare 0.45 L
slega [8]

Answer:

5.41 g

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For tetraphenyl phosphonium chloride :

Molarity = 33.0 mM = 0.033 M (As, 1 mM = 0.001 M)

Volume = 0.45 L

Thus, moles of tetraphenyl phosphonium chloride :

Moles=0.033 \times {0.45}\ moles

Moles of TPPCl = 0.01485 moles

Molar mass of TPPCl = 342.39 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.01485\ g= \frac{Mass}{342.39\ g/mol}

Mass of TPPCl = 5.0845 g

Also,

TPPCl is 94.0 % pure.

It means that 94.0 g is present in 100 g of powder

5.0845 g is present in 5.41 g of the powder.

<u>Answer -  5.41 g</u>

5 0
3 years ago
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