Answer is: empirical formula is Fe₂O₃.
m(Fe) = 7,50 g.
m(iron oxide) = 10,71 g.
n(Fe) = m(Fe) ÷ M(Fe).
n(Fe) = 7,50 g ÷ 55,85 g/mol = 0,134 mol.
m(O) = m(iron oxide) - m(Fe).
m(O) = 10,71 g - 7,50 g = 3,21 g.
n(O) = 3,21 g ÷ 16 g/mol = 0,20 mol.
n(Fe) : n(O) = 0,134 mol : 0,2 mol = 2 : 3.
The balanced equation is as below
2 N₂O₃ → 2N₂ + 3O₂
<u><em> Explanation</em></u>
According to the law of mass conservation the number of atoms in reactants side must be equal the to the number of atoms in products side.
Therefore the balanced reaction above is balanced since the number of atoms in reactants side are equal to number of atoms in products side.
For there 4 atoms of N in reactants side and 4 in products side.
Answer:
B. They are stereoisomers
C. They are enantiomers
Explanation:
Let us consider all the options
A. D and L-glucose are not necessarily furanose, they can also be in free form (open chain) or as a six-membered ring (pyranose)
B. These sugars are stereoisomers as they have the same molecular formula, same bonds but with the different spacial arrangement.
C. Two structures are called enantiomers, if they are stereoisomers and are mirror images of each other and are not-superimposable. The given pair of structures satisfy these conditions
D. Epimers are diastereoisomers (same molecular formula and connectivity having a different spacial arrangement but are not mirror images and non-superimposable) with only one different stereocenter (if there are more than one). This is not the case
E. All monosaccharides (any sugar that cannot be hydrolysed to a simpler sugar) are reducing sugars. So, this option is invalid
