<h2>
a) Acceleration due to gravity on the surface of the Moon is 1.64 m/s²</h2><h2>
b) Acceleration due to gravity on the surface of the Mars is 3.75 m/s²</h2>
Explanation:
a) Acceleration due to gravity

G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²
Mass of moon, M = 7.35 × 10²² kg
Radius of moon, r = 1.73 × 10⁶ m
Substituting

Acceleration due to gravity on the surface of the Moon is 1.64 m/s²
b) Acceleration due to gravity

G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²
Mass of Mars, M = 6.418 × 10²³ kg
Radius of Mars, r = 3.38 × 10⁶ m
Substituting

Acceleration due to gravity on the surface of the Mars is 3.75 m/s²
The correct answer among all the other choices is volts. This unit expresses the difference in energy. It is not watts or amps. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help.
Answer:
449.37412 N
Explanation:
G = Gravitational constant = 6.67259 × 10⁻¹¹ m³/kgs²
m = Mass of satellite = 438 kg
M = Mass of planet
T = Time period of the satellite = 24 h
r = Radius of planet = 
The time period of the satellite is given by

The gravitational force is given by

The force acting on this satellite is 449.37412 N