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yKpoI14uk [10]
3 years ago
6

(a) What is the acceleration due to gravity on the surface of the Moon?

Physics
1 answer:
wolverine [178]3 years ago
7 0
<h2>a)  Acceleration due to gravity on the surface of the Moon is 1.64 m/s²</h2><h2>b) Acceleration due to gravity on the surface of the Mars is 3.75 m/s²</h2>

Explanation:

a) Acceleration due to gravity

                  g=\frac{GM}{r^2}

         G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²

  Mass of moon, M = 7.35 × 10²² kg

  Radius of moon, r = 1.73 × 10⁶ m

  Substituting

                  g=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{(1.73\times 10^{6})^2}=1.64m/s^2

Acceleration due to gravity on the surface of the Moon is 1.64 m/s²

b) Acceleration due to gravity

                  g=\frac{GM}{r^2}

         G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²

  Mass of Mars, M = 6.418 × 10²³ kg

  Radius of Mars, r = 3.38 × 10⁶ m

  Substituting

                  g=\frac{6.67\times 10^{-11}\times 6.418\times 10^{23}}{(3.38\times 10^{6})^2}=3.75m/s^2

Acceleration due to gravity on the surface of the Mars is 3.75 m/s²

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Answer:

a) Vx = 1088m/s

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Explanation:

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c) The energy released or change in KE is given by:

1/2[(m1v1^2) + (m2v2^2) +(m3Vx^2) ]= MV^2

Change in KE = 1/2[ 9.4× 130^2 + 6.1 × 550^2 + 7.5 × 1088^2 ] - 1/2(23 × 130^2)

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