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3 years ago

(a) What is the acceleration due to gravity on the surface of the Moon?

1 answer:

7 0

<h2>a) Acceleration due to gravity on the surface of the Moon is 1.64 m/s²</h2><h2>b) Acceleration due to gravity on the surface of the Mars is 3.75 m/s²</h2>

Explanation:

a) Acceleration due to gravity

$g=\frac{GM}{r^2}$

G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²

Mass of moon, M = 7.35 × 10²² kg

Radius of moon, r = 1.73 × 10⁶ m

Substituting

$g=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{(1.73\times 10^{6})^2}=1.64m/s^2$

Acceleration due to gravity on the surface of the Moon is 1.64 m/s²

b) Acceleration due to gravity

$g=\frac{GM}{r^2}$

G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²

Mass of Mars, M = 6.418 × 10²³ kg

Radius of Mars, r = 3.38 × 10⁶ m

Substituting

$g=\frac{6.67\times 10^{-11}\times 6.418\times 10^{23}}{(3.38\times 10^{6})^2}=3.75m/s^2$

Acceleration due to gravity on the surface of the Mars is 3.75 m/s²

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The collective body of observations of a natural phenomenon on which scientific explanations are based is called?

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Experimental Evidence.

Scientists conduct experiments or observations to gather evidence that either support or disprove a given hypothesis. Hence, all the scientific explanations are based on this body of observations.

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3 years ago

Read 2 more answers

A car starts from rest and accelerates uniformly at 2.0 m/s2 toward the north. A second car starts from rest 4.0 s later at the

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Answer:

the correct solution is 13 s

Explanation:

This is a kinematic problem, let's use accelerated rectilinear motion relationships.

For the first car it has an accelerometer of 2.0 m/s²

x = v₀₁ t + ½ a₁ t²

The second car leaves the same point, but 4.0 seconds later

x = v₀₂ (t-4) + ½ a₂ (t-4)²

With this form we use the same time for both cars.

The initial speeds are zero for both vehicles leave the rest, at the point where they are located has the same position

x = ½ a₁ t²

x = ½ a₂ (t-4)²

Let's solve

a₁ t² = a₂ (t-4)²

a₁/a₂ t² = t² -2 4 t + 16

t² (1- 2.0 / 4.0) - 8 t +16

t² 0.5 - 8 t +16 = 0

t² -16 t + 32 = 0

Let's solve the second degree equation

t = [16 ±√( 16² - 4 32)] / 2

t = ½ (16 ± 11,3)

Solutions

t1 = 13.66 s

t2 = 2.34 s

These are the mathematical solutions for the meeting point, but car 2 leaves after 4 seconds, so the only solution is 13.66 s

the correct solution is 13 s, if you have to select one the nearest 12s

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3 years ago

A drowsy cat spots a flowerpot that sails first up and then down past an open window. the pot was in view for a total of 0.49 s,

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For this case, let's assume that the pot spends exactly half of its time going up, and half going down, i.e. it is visible upward for 0.245 s and downward for 0.245 s. Let us take the bottom of the window to be zero on a vertical axis pointing upward. All calculations will be made in reference to this coordinate system. <span>

An initial condition has been supplied by the problem:

s=1.80m when t=0.245s

<span>This means that it takes the pot 0.245 seconds to travel upward 1.8m. Knowing that the gravitational acceleration acts downward constantly at 9.81m/s^2, and based on this information we can use the formula:

s=(v)(t)+(1/2)(a)(t^2)

to solve for v, the initial velocity of the pot as it enters the cat's view through the window. Substituting and solving (note that gravitational acceleration is negative since this is opposite our coordinate orientation):

(1.8m)=(v)(0.245s)+(1/2)(-9.81m/s^2)(0.245s)^2

v=8.549m/s

<span>Now we know the initial velocity of the pot right when it enters the view of the window. We know that at the apex of its flight, the pot's velocity will be v=0, and using this piece of information we can use the kinematic equation:

(v final)=(v initial)+(a)(t)

to solve for the time it will take for the pot to reach the apex of its flight. Because (v final)=0, this equation will look like

0=(v)+(a)(t)

Substituting and solving for t:

0=(8.549m/s)+(-9.81m/s^2)(t)

t=0.8714s

<span>Using this information and the kinematic equation we can find the total height of the pot’s flight:

s=(v)(t)+(1/2)(a)(t^2) </span></span></span></span>

s=8.549m/s (0.8714s)-0.5(9.81m/s^2)(0.8714s)^2

s=3.725m<span>

This distance is measured from the bottom of the window, and so we will need to subtract 1.80m from it to find the distance from the top of the window:

3.725m – 1.8m=1.925m</span>

Answer:

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3 years ago

Asbestos would most likely be found where in a house?

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Asbestos would most likely be found <u>around pipes</u> in a house.

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Its composition is similar to thin fibers like crystals of of silicate mineral.

The fibers of Asbestos are so thin and microscopic that they liberate into the atmosphere due to erosion and other processes.

These tiny particles are considered harmful for health as they are carcinogenic in nature and causes mesothelioma.

Its melting point is between 400 to 1,040 °C and is available in blue, green, grey white and yellow color.

If you need to learn more about asbestos click here:

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1 year ago

How many neutrons does element X have if its atomic number is 48 and its mass number is 167?

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If its atomic number is 48, then it has 48 protons in the nucleus
of each atom. Any more mass than that is supplied by the neutrons
that are mixed in there with the protons.

If the mass is 167, and 48 of those are protons, then there are

(167 - 48) = 119 neutrons

in each nucleus.

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3 years ago