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3 years ago

In which situation would an object weigh the LEAST? (assume all the objects have the same mass)

Physics

2 answers:

inessss [21]3 years ago

8 0

Answer:

An object on the moon would weigh the LEAST among these. So correct answer is B.

Explanation:

Weight of an object on any place is given by:

W = Mass * Acceleration due to gravity(g)

It means when masses of different objects those are in different places are same, the weight of those objects depends upon the 'g' of that particular place.

As we know, acceleration due to gravity on surface of moon (g') is 6 times weaker than the acceleration on surface of earth (g), which is due to the large M/R^2 of the earth than the moon.

i.e. g' = g/6 so W' = W/6

And in the space between the two, the object is weightless.

Korolek [52]3 years ago

8 0

Answer:

D) an object in space closer to the moon than the Earth

Explanation:

USATestprep

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Explanation:

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2 years ago

The colors you see during a sunset are caused by _____. the refraction of light by the atmosphere the absorption of light by the

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Answer: the refraction of light by the atmosphere

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3 years ago

Two particles each of mass m and charge q are suspended by strings of length / from a common point. Find the angle e that each s

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Answer:

$\theta =\left (\frac{kq^{2}}{4L^{2}\times mg} \right )^{\frac{1}{3}}$

Explanation:

Let the length of the string is L.

Let T be the tension in the string.

Resolve the components of T.

As the charge q is in equilibrium.

T Sinθ = Fe ..... (1)

T Cosθ = mg .......(2)

Divide equation (1) by equation (2), we get

tan θ = Fe / mg

$tan\theta =\frac{\frac{kq^{2}}{AB^{2}}}{mg}$

$tan\theta =\frac{\frac{kq^{2}}{4L^{2}Sin^{\theta }}}}{mg}$

$tan\theta =\frac{kq^{2}}{4L^{2}Sin^{2}\theta \times mg}$

$tan\theta\times Sin^{2}\theta =\frac{kq^{2}}{4L^{2}\times mg}$

As θ is very small, so tanθ and Sinθ is equal to θ.

$\theta ^{3} =\frac{kq^{2}}{4L^{2}\times mg}$

$\theta =\left (\frac{kq^{2}}{4L^{2}\times mg} \right )^{\frac{1}{3}}$

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Answer:

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Explanation:

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