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3 years ago

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In which situation would an object weigh the LEAST? (assume all the objects have the same mass)

2 answers:

inessss [21]3 years ago

8 0

Answer:

An object on the moon would weigh the LEAST among these. So correct answer is B.

Explanation:

Weight of an object on any place is given by:

W = Mass * Acceleration due to gravity(g)

It means when masses of different objects those are in different places are same, the weight of those objects depends upon the 'g' of that particular place.

As we know, acceleration due to gravity on surface of moon (g') is 6 times weaker than the acceleration on surface of earth (g), which is due to the large M/R^2 of the earth than the moon.

i.e. g' = g/6 so W' = W/6

And in the space between the two, the object is weightless.

Korolek [52]3 years ago

8 0

Answer:

D) an object in space closer to the moon than the Earth

Explanation:

USATestprep

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The table below shows some common animals and their hearing range in Hertz (Hz). Animal Hearing Range in Rate of Vibrations per

kap26 [50]

Answer:

D

Explanation:

If you list and compare, the elephants hearing range is the closest to a humans.

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3 years ago

A biker first accelerates from 0.0 m/s to 6.0 m/s in 6 s, then continues at this speed for 5 s. What is the total distance trave

Svetradugi [14.3K]

Answer:

48m

Explanation:

Given the following data;

Initial velocity = 0m/s

Final velocity = 6m/s

Time, t = 6 secs

Time, T2 = 5 secs

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$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

Substituting into the equation;

$a = \frac{6 - 0}{6}$

$a = \frac{6}{6}$

Acceleration, a = 1m/s²

<u>To find the distance covered in the first phase;</u>

<em>Solving for distance, we would use the second equation of motion;</em>

$S = ut + \frac {1}{2}at^{2}$

<em>Substituting the values into the equation;</em>

$S = 0(6) + \frac {1}{2}*1*(6)^{2}$

$S = 0 + \frac {1}{2}*1*36$

$S = 0.5 *36$

Distance, S1 = 18m

<u>For the second phase, time T2 = 5 secs;</u>

<em>Mathematically, speed is given by the equation;</em>

$Speed = \frac{distance}{time}$

<em>Making distance the subject of formula, we have;</em>

$Distance, S = speed * time$

<em>Substituting into the above equation;</em>

$Distance, S = 6 * 5$

Distance, S2 = 30m

Total distance = S1 + S2 = 18m + 30m = 48m

Total distance = 48m

<em>Therefore, the total distance traveled by the biker is 48m.</em>

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