PLEASE HELP REALLY IMPORTANT
1 answer:
You might be interested in
The question is incomplete, here is the complete question:
At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1 M⁻¹s⁻¹
Suppose a vessel contains SO₃ at a concentration of 1.44 M. Calculate the concentration of SO₃ in the vessel 0.240 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits.
<u>Answer:</u> The concentration of in the vessel after 0.240 seconds is 0.24 M
<u>Explanation:</u>
For the given chemical equation:
The integrated rate law equation for second order reaction follows:
where,
k = rate constant =
t = time taken= 0.240 second
[A] = concentration of substance after time 't' = ?
= Initial concentration = 1.44 M
Putting values in above equation, we get:
Hence, the concentration of in the vessel after 0.240 seconds is 0.24 M