<h2>Hello!</h2>
The answer is: -97.37° C
<h2>Why?</h2>
According to the Charles and Gay-Lussac's Law we have that:
![\frac{V}{T}=k](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7BT%7D%3Dk)
Where:
<em>v</em> is the volume of the gas
<em>t</em> is the temperature of the gas
<em>k </em>is the proportionality constant
From the Gay-Lussac's Law we also have the following relation:
![\frac{V1}{T1}=\frac{V2}{T2}](https://tex.z-dn.net/?f=%5Cfrac%7BV1%7D%7BT1%7D%3D%5Cfrac%7BV2%7D%7BT2%7D)
Since we need to find the new temperature (T2) we can use the last equation:
![\frac{V1}{T1}=\frac{V2}{T2}\\\\T2=\frac{V2*T1}{V1}=\frac{16.2L*278K}{25.6L}=175.92K](https://tex.z-dn.net/?f=%5Cfrac%7BV1%7D%7BT1%7D%3D%5Cfrac%7BV2%7D%7BT2%7D%5C%5C%5C%5CT2%3D%5Cfrac%7BV2%2AT1%7D%7BV1%7D%3D%5Cfrac%7B16.2L%2A278K%7D%7B25.6L%7D%3D175.92K)
We are asked to find the temperature in Celsius degrees, so, we must convert the result (in K) to Celsius degrees:
![Celsius=K-273.15=175.92-273.15=-97.37](https://tex.z-dn.net/?f=Celsius%3DK-273.15%3D175.92-273.15%3D-97.37)
So, the temperature is -97.37° C
Have a nice day!
Answer:
The electrons where in motion
Answer:
color is there right answer for this question please make me a brainliest and follow me please please please please
Answer: ( Outwash )
hope this helps!
Answer:
Check the explanation
Explanation:
When,
pH = -log[H+] = 3.30
[H+] = ![5.0 X 10^{-4} M](https://tex.z-dn.net/?f=5.0%20X%2010%5E%7B-4%7D%20M)
![Ka1 = 1 ; Ka2 = 0.0316 ; Ka3 = 0.01 ; Ka4 = 0.002 ; Ka5 = 7.4 X 10^{-7} ; Ka6 = 4.3 X 10^{-11}](https://tex.z-dn.net/?f=Ka1%20%3D%201%20%3B%20Ka2%20%3D%200.0316%20%3B%20Ka3%20%3D%200.01%20%3B%20Ka4%20%3D%200.002%20%3B%20Ka5%20%3D%207.4%20X%2010%5E%7B-7%7D%20%3B%20Ka6%20%3D%204.3%20X%2010%5E%7B-11%7D)
![alpha[Y^-4] = [H+]^6 + Ka1[H+]^5 + Ka1Ka2[H+]^4 + Ka1Ka2Ka3[H+]^3 + Ka1Ka2Ka3Ka4[H+]^2 + Ka1Ka2Ka3Ka4Ka5[H+] + Ka1Ka2Ka3Ka4Ka5Ka6](https://tex.z-dn.net/?f=alpha%5BY%5E-4%5D%20%3D%20%5BH%2B%5D%5E6%20%2B%20Ka1%5BH%2B%5D%5E5%20%2B%20Ka1Ka2%5BH%2B%5D%5E4%20%2B%20Ka1Ka2Ka3%5BH%2B%5D%5E3%20%2B%20Ka1Ka2Ka3Ka4%5BH%2B%5D%5E2%20%2B%20Ka1Ka2Ka3Ka4Ka5%5BH%2B%5D%20%2B%20Ka1Ka2Ka3Ka4Ka5Ka6)
= ![1.56 X 10^{-20} + 3.12 X 10^{-17} + 2 X 10^{-15} + 4 X 10^{-14} + 1.6 X 10^{-13} + 2.34 X 10^{-16} + 2 X 10^{-23}](https://tex.z-dn.net/?f=1.56%20X%2010%5E%7B-20%7D%20%2B%203.12%20X%2010%5E%7B-17%7D%20%2B%202%20X%2010%5E%7B-15%7D%20%2B%204%20X%2010%5E%7B-14%7D%20%2B%201.6%20X%2010%5E%7B-13%7D%20%2B%202.34%20X%2010%5E%7B-16%7D%20%2B%202%20X%2010%5E%7B-23%7D)
= ![2.02 X 10^{-13}](https://tex.z-dn.net/?f=2.02%20X%2010%5E%7B-13%7D)
When,
pH = -log[H+] = 10.15
[H+] = ![7.08 X 10^{-11} M](https://tex.z-dn.net/?f=7.08%20X%2010%5E%7B-11%7D%20M)
Ka1 = 1 ; Ka2 = 0.0316 ; Ka3 = 0.01 ; Ka4 = 0.002 ; Ka5 =
; Ka6 = ![4.3 X 10^-11](https://tex.z-dn.net/?f=4.3%20X%2010%5E-11)
= ![1.26 X 10^{-61} + 1.8 X 10^{-51} + 8.1 X 10^{-43} + 1.12 X 10^{-34} + 3.17 X 10^{-27} + 3.3 X 10^{-23} + 1.83 X 10^{-23}](https://tex.z-dn.net/?f=1.26%20X%2010%5E%7B-61%7D%20%2B%201.8%20X%2010%5E%7B-51%7D%20%2B%208.1%20X%2010%5E%7B-43%7D%20%2B%201.12%20X%2010%5E%7B-34%7D%20%2B%203.17%20X%2010%5E%7B-27%7D%20%2B%203.3%20X%2010%5E%7B-23%7D%20%2B%201.83%20X%2010%5E%7B-23%7D)
= ![5.12 X 10^{-23}](https://tex.z-dn.net/?f=5.12%20X%2010%5E%7B-23%7D)