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Otrada [13]
3 years ago
8

Explain the value of observations during an investigation and suggest one way that you can ensure good observations when you do

scientific work
Chemistry
1 answer:
Nastasia [14]3 years ago
6 0
<span>Observation is an important part of investigation.Small evidence may become the key factor for success. Observation is the active acquisition of information from a primary source. In living beings, observation employs the senses. In science, observation can also involve the recording of data via the use of instruments. The term may also refer to any data collected during the scientific activity.</span>
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Is mayonnaise an element compound solution or colloids
Alenkinab [10]
The answer to your question is mayonnaise is colloids.
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3 years ago
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Calculate the amount of grams of water that was used when 5525J of energy was used to boil this amount of water.
djverab [1.8K]

Answer:

2.445 g

Explanation:

Step 1: Given and required data

  • Energy in the form of heat required to boil the water (Q): 5525 J
  • Latent heat of vaporization of water (∆H°vap): 2260 J/g
  • Mass of water (m): ?

Step 2: Calculate the mass of water

We will use the following expression.

Q = ∆H°vap × m

m = Q / ∆H°vap

m = 5525 J / (2260 J/g)

m = 2.445 g

4 0
3 years ago
What happens when soluble fiber is mixed with water?
storchak [24]

Answer:

Soluble fiber attracts water and turns to gel during digestion. This slows digestion. Soluble fiber is found in oat bran, barley, nuts, seeds, beans, lentils, peas, and some fruits and vegetables. It is also found in psyllium, a common fiber supplement.:

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3 years ago
The addition of a catalyst to a chemical reaction provides an alternate pathway that
Degger [83]
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4 0
4 years ago
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Calculate the heat absorbed by the water in a calorimeter when 175 grams of lead cools from 125.0°C to 22.0°C. The specific heat
Iteru [2.4K]

Answer:

Q = 233.42 J

Explanation:

Given data:

Mass of lead = 175 g

Initial temperature = 125.0°C

Final temperature = 22.0°C

Specific heat capacity of lead = 0.01295 J/g.°C

Heat absorbed by water = ?

Solution:

Heat  absorbed by water is actually the heat lost by the metal.

Thus, we will calculate the heat lost by metal.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 22.0°C - 125.0°C

ΔT = -103°C

Q = 175 g × 0.01295 J/g.°C×-103°C

Q = -233.42 J

Heat absorbed by the water is 233.42 J.

5 0
3 years ago
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