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Maksim231197 [3]
3 years ago
9

How many grams of CO2could be produced from the combustion of 23g of C4H10in the presence of an adequate amount of O2?

Chemistry
1 answer:
blsea [12.9K]3 years ago
8 0

Answer:

Mass = 70.4 g

Explanation:

Given data:

Mass of CO₂ produced = ?

Mass of C₄H₁₀ = 23 g

Solution:

Chemical equation:

2C₄H₁₀ + 13O₂  →   8CO₂ + 10H₂O

Number of moles of C₄H₁₀:

Number of moles = mass/ molar mass

Number of moles = 23 g/ 58.12 g/mol

Number of moles = 0.4 mol

Now we will compare the moles of C₄H₁₀ and  CO₂  from balance chemical equation.

                   C₄H₁₀          :           CO₂

                        2             :             8

                      0.4           :          8/2×0.4 = 1.6 mol

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 1.6 mol × 44 g/mol

Mass = 70.4 g

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3 years ago
An alkaline solution has more hydrogen ions then hydroxide ions.<br><br> a. True<br><br> b. False
ANTONII [103]

Answer:

True

Explanation:

When a base is dissolved in water, the balance between hydrogen ions and hydroxide ions shifts the opposite way. Because the base "soaks up" hydrogen ions, the result is a solution with more hydroxide ions than hydrogen ions. This kind of solution is alkaline.

8 0
3 years ago
B) calculate the ratio of moles of h2o to moles of anhydrous kal(so4)2. note: report the ratio to the closest whole number. (sho
Sindrei [870]

Answer: -

Mass of Hydrated KAl(SO₄)₂ = 2.0 g

Molar mass of anhydrous KAl(SO₄)₂ = 258.20 g/ mol

Mass of of anhydrous KAl(SO₄)₂ = mass of the 2nd heating = A

The mass of water released = mass of the Aluminum Cup + 2.0 grams of KAl(SO₄)₂ - mass of the 2nd heating

= H g

Moles of water released = \frac{H g}{18 g/mol}

Moles of anhydrous KAl(SO₄)₂ = \frac{A g}{258.20 g/mol}

Required ratio = \frac{moles of water}{moles of anhydrous KAl(SO4)2}

5 0
3 years ago
A 1.362 g sample of an iron ore that contained Fe3O4 was dissolved in acid with all of the iron being reduced to iron (II). The
Natasha2012 [34]

Answer:

a. MnO₄⁻ + 8H⁺ + 5Fe²⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O

b. 18.17% of Fe in the sample

Explanation:

a. In the reaction, Fe²⁺ is oxidized to Fe³⁺ and permanganate, MnO₄⁺ reduced to Mn²⁺, thus:

Fe²⁺ → Fe³⁺ + 1e⁻

MnO₄⁻ + 5e⁻ + 8H⁺ → Mn²⁺ + 4H₂O

5 times the iron and suming the manganese reaction:

MnO₄⁻ + 5e⁻ + 8H⁺ + 5Fe²⁺ → 5Fe³⁺ + 5e⁻ + Mn²⁺ + 4H₂O

<h3>MnO₄⁻ + 8H⁺ + 5Fe²⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O</h3>

b. Moles of permanganate in the titration are:

0.03942L × (0.0281 moles / L) = <em>1.108x10⁻³ moles of MnO₄⁻</em>

Based on the reaction, 1 mole of permanganate reacts with 5 moles of iron, if 1.108x10⁻³ moles of MnO₄⁻ reacts, moles of iron are:

1.108x10⁻³ moles of MnO₄⁻ × (5 moles Fe²⁺ / 1 mole MnO₄⁻) =

<em>4.431x10⁻³ moles of Fe²⁺</em>. Molar mass of Fe is 55.845g/mol. 4.431x10⁻³ moles of Fe²⁺ are:

4.431x10⁻³ moles of Fe²⁺ ₓ (55.845g / mol) =

<h3>0.2474g of Fe you have in your sample.</h3>

Percent mass is:

0.2474g Fe / 1.362g sample ₓ 100 =

<h3>18.17% of Fe in the sample</h3>
6 0
3 years ago
Which of the following adaptations found in animals in deciduous forests protects against predators?
statuscvo [17]

Answer:

The answer is D. Camouflage

7 0
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