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Lady_Fox [76]
3 years ago
12

The atmospheric pressure on a mountain is 550 mmHg and 1 atm is equal to 760 mmHg. What is the pressure in atm? Give your answer

to 2 significant figures760 mmHg what is the pressure in atm?
Physics
1 answer:
Svetradugi [14.3K]3 years ago
4 0

Answer:

0.72 atm

Explanation:

Given that the atmospheric pressure on a mountain is 550 mmHg.

Where 1 atm is equal to 760 mmHg.

To Convert millimetre mercury (mmHg) into atmospheric pressure units (atm) , divide the magnitude of pressure by 760. That is,

Pressure = 550/760

Pressure = 0.724 atm

Therefore, pressure in atm is 0.72 atm in two significant figures

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Then, the total charge is the number of protons times the charge of a  single proton:
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An object moving in circular motion has a mass of 15 kg and a centripetal acceleration of 10 m/s2. What is the centripetal force
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Answer:

1) A

2) C

3) B

4) A

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6) Incomplete information(picture missing)

7) Incomplete information(picture missing)

8) A

9) C

10) C

Explanation:

1) m = 15kg, a = 10ms^{-2}, F = ma = 15*10 = 150N

2) m = 3kg, v = 4ms^{-1}, r = 4m, F = \frac{mv^{2} }{r}

\frac{3*4^{2} }{4} = 12N

3) a = 10ms^{-2}, r = 10m, v=?

F = \frac{mv^{2} }{r} and F = ma

equating the two equations and cancelling a, we have:

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making v the subject of formula, we have:

v = \sqrt{ar}

= \sqrt{100}

= 10ms^{-1}

4) r = 10m, v = 5ms^{-1}, a = ?

F = \frac{mv^{2} }{r}

F = ma

equating the above equations and making a subject of formula, we get:

a = \frac{v^{2} }{r}

a = 25/10 = 2.5ms^{-2}

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6) I can't find the picture associated with this question

7) I can't find the picture associated with this question

8) F = \frac{mv^{2} }{r}

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = v^{2}

Now, if v is tripled

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We can see that the force will be 9X greater than it was.

9) F = \frac{mv^{2} }{r}

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = v^{2}

Now, if v is doubled

F = (2v)^{2}

F = 4v^{2}

We can see that the force will be 4X greater than it was.

10) F = \frac{mv^{2} }{r}

assuming m and v is unity, that is the values are 1 respectively

F = 1/r

if r is doubled,

F = 1/2 * 1/r

We can see that the force is 1/2 as big as it was

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