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GaryK [48]
3 years ago
13

If you want points for your account just answer yes

Physics
1 answer:
jeka943 years ago
5 0

Answer:

Lol, yes

Explanation:

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What happens to a sheet of copper as kinetic energy of copper molecules decrease
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First is melts then it expands next it gets cooler Finally it gains ener. Hope this helps you out.
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3 years ago
Engineers have designed experimental cars that use liquid hydrogen for fuel instead of gasoline. this is an example of _____. re
olasank [31]

Engineers have designed experimental cars that use liquid hydrogen for fuel instead of gasoline. this is an example of Substitution.


Substitution is the process where one thing replaces other for a particular purpose. here liquid hydrogen is replacing the gasoline for fuel in car. hence the correct word to fill is Substitution.

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In our solar system, most asteroids are found _____.A.In the kuiper beltb.Orbiting close to the sunc.Between mars and jupiterd.B
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3 years ago
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A block slides down a slope inclined at 37 degrees. If the slope is frictionless and the block starts off at rest, how fast is i
lianna [129]

Answer:

Vf= 3.435 m/s

Explanation:

Given:

Initial velocity Vi =0 m/s (starting from Rest position)

θ = 37⁰

Distance S = 1 m

To find: Final Velocity Vf=?

fist we have to find the down slope net acceleration a = g sin θ

a= 9.81 sin  37⁰ = 5.9 m/s²

By 3rd equation of motion

2 a S= Vf² - Vi²

Vf = Square root ( 2 × 5.9 m/s²  × 1  + 0 m/s)

Vf = Square root (11.8)

Vf= 3.435 m/s

3 0
2 years ago
Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm
cestrela7 [59]

Answer:

0.043 m

Explanation:

From the attachment, the shaded part is the ethyl alcohol. The crossed part on the other hand, is that of glycerin.

The height of the Ethyl Alcohol is h2 = 0.25 m, it's density is ρ2 = 790 kg/m³. The density of glycerin is ρ1 = 1260 kg/m³

If we assume pressure at the two points to be the same, then

P1 = P2

ρ1.g.V1 = ρ2.g.V2

ρ1.A.h1 = ρ2.A.h2

ρ1.h1 = ρ2.h2, making h1 subject of formula

h1 = ρ2.h2 / ρ1, so that

h1 = 790 * 0.25 / 1260

h1 = 197.5 / 1260

h1 = 0.157 m

Δh = 0.2 - 0.157

Δh = 0.043 m or 4.3 cm

8 0
2 years ago
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