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RoseWind [281]
3 years ago
13

The graph below is called a heating curve. It shows how water changes from one state of matter to another based on temperature a

nd the addition or removal of heat over time. At which point on the graph would water be entirely gas?

Physics
2 answers:
Dimas [21]3 years ago
8 0

Answer:

the answer is D.

Neporo4naja [7]3 years ago
4 0

Explanation :

The heating curve shows how water changes from one state of matter to another based on temperature and the addition or removal of heat over time.

Initially, ice is heated until its temperature reaches 0^0\ C and changes to liquid state.

From the attached graph it is clear that until 100^0\ C the temperature will rise steadily. Here, the liquid begins to vaporize. Vaporization is the state of matter at which liquid state changes to the gaseous state.

So, E is the point which shows the gaseous state.

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A 3 Hz wave has a wavelength of 0.4 m. Calculate the speed of the wave (in m/s).
anyanavicka [17]

The speed of the wave with the given frequency and wavelength is 1.2m/s.

Given the data in the question;

  • Wavelength of the wave; \lambda = 0.4m
  • Frequency; f = 3Hz = 3s^{-1}
  • Speed of the wave; v = \ ?

<h3>Wavelength</h3>

Wavelength is  the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.

It is expressed as;

\lambda = \frac{v}{f}

Where v is velocity/speed and f is frequency.

Now, we can easily get the speed of the wave by substituting our given values into the expression above.

\lambda = \frac{v}{f} \\\\0.4m = \frac{v}{3s^{-1}}\\ \\v = 0.4m * 3s^{-1}\\\\v = 1.2ms^{-1}\\\\v = 1.2m/s

Therefore, the speed of the wave with the given frequency and wavelength is 1.2m/s.

Learn more about Speed, Frequency and Wavelength here: brainly.com/question/27120701

8 0
2 years ago
A 3,65 kg mass attached to a
motikmotik

This question involves the concepts of tension, weight, and centripetal force.

The maximum speed, the mass can have before the string breaks is "10.26 m/s".

First, we will find the maximum tension force:

Tension = Weight

T = W = mg = (32.4 kg)(9.81 m/s²)

T = 317.84 N

Now, this tension force must be equal to the centripetal force:

T = \frac{mv^2}{r}\\v=\sqrt{\frac{Tr}{m}}

where,

v = maximum speed = ?

r = radius = 1.21 m

m = mass = 3.65 kg

Therefore,

v=\sqrt{\frac{(317.84\ N)(1.21\ m)}{3.65\ kg}}\\

<u>v = 10.26 m/s</u>

Learn more about centripetal force here:

brainly.com/question/11324711?referrer=searchResults

The attached picture shows the centripetal force.

8 0
2 years ago
The following represents a mass attached to a spring oscillating in simple harmonic motion. X(t) = 4.0 cos(3.0t +0.10) units of
kolbaska11 [484]

Answer:

a) A = 4.0 m , b)   w = 3.0 rad / s , c)  f = 0.477 Hz , d) T = 20.94 s

Explanation:

The equation that describes the oscillatory motion is

          x = A cos (wt + fi)

In the exercise we are told that the expression is

          x = 4.0 cos (3.0 t + 0.10)

let's answer the different questions

a) the amplitude is

         A = 4.0 m

b) the frequency or angular velocity

         w = 3.0 rad / s

c) angular velocity and frequency are related

          w = 2π f

           f = w / 2π

           f = 3 / 2π

           f = 0.477 Hz

d) the period

frequency and period are related

           T = 1 / f

           T = 1 / 0.477

           T = 20.94 s

e) the phase constant

          Ф = 0.10 rad

f) velocity is defined by

          v = dx / dt

         

         v = - A w sin (wt + Ф)

speed is maximum when sine is + -1

         v = A w

          v = 4 3

          v = 12 m / s

g) the angular velocity is

          w² = k / m

          k = m w²

          k = 1.2 3²

          k = 10.8 N / m

h) the total energy of the oscillator is

          Em = ½ k A²

           Em = ½ 10.8 4²

          Em = 43.2 J

i) the potential energy is

           Ke = ½ k x²

for t = 0 x = 4 cos (0 + 0.1)

               x = 3.98 m

j) kinetic energy

           K = ½ m v²

for t = 00.1 ²

    v = A w sin 0.10

    v = 4 3 sin 0.10

    v = 1.98 m / s

3 0
3 years ago
An astronaut holds a rock 100 m above surface of Planet X. The rock is then thrown upwards with a sleek of 15m/s. The rock reach
Gelneren [198K]

Answer:5 m/s^{2}

Explanation:

This problem is related to vertical motion, and the equation that models it is:

y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2} (1)

Where:

y=0m is the rock's final height

y_{o}=100 m is the rock's initial height

V_{o}=15 m/s is the rock's initial velocity

\theta=90\° is the angle at which the rock was thrown (directly upwards)

t=10 s is the time

g is the acceleration due gravity in Planet X

Isolating g and taking into account sin(90\°)=1 :

g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t) (2)

g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s)) (3)

g=5 m/s^{2} (4) This is the acceleration due gravity in Planet X

5 0
3 years ago
A team of engineers is working together to design a new airplane. The team members each live in different cities. For which purp
Ierofanga [76]

Answer:

The internet is most useful to them because they use it to communicate.

Explanation:

If I were to send a message to my brother in Florida, through the internet, while I'm in Pennsylvania he would get it in minutes. On the other hand if I were going to meet him and then explain what I wanted to tell him in person it would take a much longer time.  

8 0
3 years ago
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