Answer:work function= 8.2×10-19J
Minimum wavelength of light required= 2.4×10-7m
Explanation:
The wavelength of incident light was given as 193nm. We have to convert this to meters and have 193×10-9m. Then we use it to find the energy of incident photon E. When E is found we now apply Einstein photoelectric equation to obtain the work function Wo since the kinetic energy of photoelectrons is known as 1.8×10-19J.
From this work function. We can obtain the minimum wavelength of light required. All these steps are shown in the image attached.
<u>Answer:</u> The partial pressure of nitrogen on Venus is 81 mmHg
<u>Explanation:</u>
To calculate the partial pressure of the gas, we use the equation given by Raoult's law, which is:
where,
= partial pressure of nitrogen gas = ?
= total pressure = 2700 mmHg
= mole fraction of nitrogen gas = 3.0 % = 0.03
Putting values in above equation, we get:
Hence, the partial pressure of nitrogen on Venus is 81 mmHg
An example is when light goes from traveling on air to the water. A famous experiment that is done on many schools to prove this is the one with the pencil on a cup of water. I added both pictures so you are able to visualise what I'm trying to say. The pencil "bends" on the water because of a phenomenon called refraction. <span>When light enters water, it cannot move as fast as it </span>does in air, therefore, a<span>s the light enters the water, it </span>bends<span> away from its original path. Hope I was able to help!!</span>
Answer:
ΔH = -746.6kJ
Explanation:
Using Hess's law we can find the ΔH of a reaction from the sum of similar reactions. From the reactions:
1. 2CO(g) + O2(g) → 2CO2 ΔH = -566.0kJ
2. N2(g) + O2(g) → 2NO(g) ΔH = 180.6kJ
The negative reaction of 2:
-2. 2NO(g) → N2(g) + O2(g) ΔH = -180.6kJ
The sum of 1 - 2:
2CO(g) + O2(g) + 2NO(g) → 2CO2 N2(g) + O2(g) ΔH = -566.0kJ + (-180.6kJ) =
ΔH = -746.6kJ
Subtracting the molecules that don't change:
2CO(g) + 2NO(g) → 2CO2 + N2(g) ΔH = -746.6kJ
Principal (shell) quantum number - n
<span>Describes the energy level in the atom (1 through 7)<span>The maximum number of electrons in n is <span>2n2</span></span></span><span> </span>
<span>2. Angular (subshell) quantum number - </span>l
<span><span>Describes the sublevel in n</span><span>Each energy level has n sublevels</span></span><span> </span>
<span>3. Magnetic quantum number - </span>m
<span><span>Describes the orbital within l</span>s has 1 orbitalp has 3 orbitalsd has 5 orbitalsf has 7 orbitals</span><span> </span>
<span>4. Spin quantum number - </span>s
<span>Describes the spin of the electrons in an orbital.Electrons in the same orbital must have oppisite spins.<span>Possible spins are clockwise or counterclockwise.</span></span>
