Write the verbal expression for each algebraic expression.

Mathematics

1 answer:

sukhopar [10]3 years ago

7 0

Step-by-step explanation:

i hope it helped you a lot. thankyou

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Need help with trigonometry

vovangra [49]

Answer:

$\sf \tan(A) & =\dfrac{9\sqrt{22}}{44}$

Step-by-step explanation:

If angle C is the right angle, then side c is the hypotenuse.

Use Pythagoras' Theorem $a^2+b^2=c^2$ to find the length of side a:

Given:

b = 2√22
c = 13

$\implies a^2+(2 \sqrt{22})^2=13^2$

$\implies a^2+88=169$

$\implies a^2=81$

$\implies a=\sqrt{81}$

$\implies a=9$

<u>Tan Trig Ratio</u>

$\sf \tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle

Given:

$\theta$ = A
O = side opposite angle A = a = 9
A = side adjacent angle A = b = 2√22

$\begin{aligned}\implies \sf \tan(A) & =\dfrac{9}{2\sqrt{22}}\\\\ & =\dfrac{9}{2\sqrt{22}} \times \dfrac{\sqrt{22}}{\sqrt{22}}\\\\ & = \dfrac{9\sqrt{22}}{44} \end{aligned}$

6 0

1 year ago

Read 2 more answers

A train goes twice as fast downhill as it can go uphill, and 2/3 feet as fast uphill as it can go on level ground. If it goes 12

Yuri [45]

Answer:

0.5hrs

Step-by-step explanation:

Let the speed downhill be $x$ ,

Speed uphill is $0.5x$ . We are told than speed uphill is $\frac{2}{3}$ the speed on flat ground. Therefore the speed on level ground will be $\frac{0.5x}{2/3}=0.75x$ .