Answer:
Total energy is 170 kJ
Explanation:
Given data:
latent heat of fusion of alcohol is 25 kcal/kg
melting point of alcohol is -114 degree c
specific heat us 0.60 k cal/kg degree c
energy need for 2 kg solid alcohol is
for Melting:
Energy Q is calculated as
Energy, Q = 25 \times 2.0 kg = 50 kJ
Energy required for Heating liquid:
Energy, ΔH = 2.0 kg \times 0.60 \times (100°C) = 120 kJ
Total energy = (50 kJ + 120 kJ) = 170 kJ
Answer:
The cable run exceeds the specifications for Ethernet over twisted pair
Explanation:
The ethernet network's router also serves as a bridge to the Internet. The router connects to the modem, which carries the Internet signal, sending and receiving data packet requests and routing them to the proper computers on the network.
Ethernet is a way of connecting computers together in a local area network or LAN. It has been the most widely used method of linking computers together in LAN s since the 1990 s.
The basic idea of its design is that multiple computers have access to it and can send data at any time.
Answer:
145 m
Explanation:
Given:
Wavelength (λ) = 2.9 m
we know,
c = f × λ
where,
c = speed of light ; 3.0 x 10⁸ m/s
f = frequency
thus,
![f=\frac{c}{\lambda}](https://tex.z-dn.net/?f=f%3D%5Cfrac%7Bc%7D%7B%5Clambda%7D)
substituting the values in the equation we get,
![f=\frac{3.0\times 10^8 m/s}{2.9m}](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B3.0%5Ctimes%2010%5E8%20m%2Fs%7D%7B2.9m%7D)
f = 1.03 x 10⁸Hz
Now,
The time period (T) = ![\frac{1}{f}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D)
or
T =
= 9.6 x 10⁻⁹ seconds
thus,
the time interval of one pulse = 100T = 9.6 x 10⁻⁷ s
Time between pulses = (100T×10) = 9.6 x 10⁻⁶ s
Now,
For radar to detect the object the pulse must hit the object and come back to the detector.
Hence, the shortest distance will be half the distance travelled by the pulse back and forth.
Distance = speed × time = 3 x 10^8 m/s × 9.6 x 10⁻⁷ s) = 290 m {Back and forth}
Thus, the minimum distance to target =
= 145 m
Answer:
The ratio of the pressure at the top to the pressure at the bottom is ![\dfrac{701}{1000}](https://tex.z-dn.net/?f=%5Cdfrac%7B701%7D%7B1000%7D)
Explanation:
Given that,
Number of molecules ![n= 10^24](https://tex.z-dn.net/?f=n%3D%2010%5E24)
Mass ![m= 3\times10^{-26}\ kg](https://tex.z-dn.net/?f=m%3D%203%5Ctimes10%5E%7B-26%7D%5C%20kg)
Temperature = 300 K
Height ![h = 5\times10^{3}](https://tex.z-dn.net/?f=h%20%3D%205%5Ctimes10%5E%7B3%7D)
We need to calculate the ratio of the pressure at the top to the pressure at the bottom
Using barometric formula
![P_{h}=P_{0}e^{\dfrac{-mgh}{kT}}](https://tex.z-dn.net/?f=P_%7Bh%7D%3DP_%7B0%7De%5E%7B%5Cdfrac%7B-mgh%7D%7BkT%7D%7D)
![\dfrac{P_{h}}{P_{0}}=e^{\dfrac{-mgh}{kT}}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_%7Bh%7D%7D%7BP_%7B0%7D%7D%3De%5E%7B%5Cdfrac%7B-mgh%7D%7BkT%7D%7D)
Where, m = mass
g = acceleration due to gravity
h = height
k = Boltzmann constant
T = temperature
Put the value in to the formula
![\dfrac{P_{h}}{P_{0}}=e^{\dfrac{-3\times10^{-26}\times9.8\times5\times10^{3}}{1.3807\times10^{-23}\times300}}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_%7Bh%7D%7D%7BP_%7B0%7D%7D%3De%5E%7B%5Cdfrac%7B-3%5Ctimes10%5E%7B-26%7D%5Ctimes9.8%5Ctimes5%5Ctimes10%5E%7B3%7D%7D%7B1.3807%5Ctimes10%5E%7B-23%7D%5Ctimes300%7D%7D)
![\dfrac{P_{h}}{P_{0}}=\dfrac{701}{1000}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_%7Bh%7D%7D%7BP_%7B0%7D%7D%3D%5Cdfrac%7B701%7D%7B1000%7D)
Hence, The ratio of the pressure at the top to the pressure at the bottom is ![\dfrac{701}{1000}](https://tex.z-dn.net/?f=%5Cdfrac%7B701%7D%7B1000%7D)
Answer:
50m [N]
Explanation:
Think of these directions as if they were on a 2D plane. (if you're talking about displacement)
If you go 32m [N] then 6m [S], it's like you're moving backwards (-). (thus, 32n-6s=26m [N])
Next, you go north again, so moving forwards (+). (thus, 26n+24n=50m [N])