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riadik2000 [5.3K]
3 years ago
13

An astronomer is observing a nearby star system in an attempt to determine whether it is made up of one or two stars. If the sta

r system is 4.1 light-years away and she is observing with blue light (400 nm) using a telescope with a 7.4 meter circular primary mirror, how far apart must the stars be (perpendicular to the line of sight) in order for her to tell them apart
Physics
1 answer:
Nikolay [14]3 years ago
7 0

Answer:

x = 2.6 10⁹ m

Explanation:

In order to differentiate the two stars, you must apply the Rayleigh criterion, which establishes that the objects are separated if the maximum diffraction of one coincides with the first minute of diffraction of the other.

Based on this, the diffraction for slits with m = 1

                sin θ = λ / a

as the angles are very small

                sin θ = θ

               θ = λ / a

if instead of slits we use circular openings, the problem must be solved in polar coordinates, giving

                θ = 1.22 λ /D

let's calculate

                θ = 1.22 400 10⁻⁹ / 7.4

                θ = 6.59 10⁻⁸ rad

this is the tiny angle to be able to see the stars separately, if we use the definition of radians

               θ = x / R

where R is the distance to the system

             x =  θ R

           

let's reduce the distance to the SI system

             R = 4.1 light-years (9.461 10¹⁵ m / 1 light-year)

             R = 3.88 10¹⁶ m

let's calculate

             x = 6.59 10⁻⁸ 3.88 10¹⁶

             x = 2.6 10⁹ m

this is the minimum distance between the two stars to be able to differentiate them

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A particle initially at rest moves along in a line so that its acceleration is a(t) = 10/(t+1) for t>=0.
ddd [48]

Answer: 16.09m/s

Explanation:

Given the acceleration a(t) = 10/(t+1), to derive the velocity function, we need integrate the acceleration function.

v(t) = integral{10/t+1}dt

Since all constants always come out of the integral, the equation becomes;

v(t) = 10integral{1/t+1}dt

One of the integral law is that if the numerator of the function to be integrated is the differential of the denominator, the resulting answer will be natural logarithm of the denominator i.e ln(t+1) since the denominator is ln(t+1) and if differentiated will give us 1 which is the numerator hence, the reason for the answer ln(t+1)

v(t) = 10ln(t+1)

@ t= 4, the velocity of the particle

v(4) = 10ln(4+1)

v(4) = 10ln5

v(4) = 16.09m/s²

Therefore, the velocity of the particle at time t=4 is 16.09m/s

4 0
3 years ago
A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 800.0 kg t
Stella [2.4K]

Answer:

Explanation:

mass of car, m1 = 1170 kg

mass of truck, m2 = 9800 kg

initial velocity of car, u1 = 25 m/s

initial velocity of truck, u2 = 20 m/s

final velocity of car, v1 = 18 m/s

Let the final velocity of truck is v2.

(a) Use the conservation of momentum

m1 x u1 + m2 x u2 + m1 x v1 + m2 x v2

1170 x 25 + 9800 x 20 = 1170 x 18 + 9800 x v2

29250 + 196000 = 21060 + 9800 v2

v2 = 20.84 m/s

(b) Total kinetic energy before collision,

Ki = 0.5 x 1170 x 25 x 25 + 0.5 x 9800 x 20 x 20

Ki = 365625 + 1960000 = 2325625 J

Total final kinetic energy

Kf = 0.5 x 1170 x 18 x 18 + 0.5 x 9800 x 20.84 x 20.84

Kf = 189540 + 2128097.44

Kf = 2317637.44 J

Change in energy = 2325625 - 2317637.44 = 7987.56 J

(c) It is due to the heat energy

4 0
4 years ago
A boat travels north at a rate of 25.0 kilometers per hour (km/hr) relative to the current of the river. The current of the rive
USPshnik [31]

Answer:yes

Explanation:yes

4 0
3 years ago
Forces cause changes to the motion of objects. Name a force and describe two changes it makes.
otez555 [7]
Sliding and Static.

Would be the right one here.
3 0
4 years ago
There are two different size spherical paintballs and the smaller one has a diameter of 5 cm and the larger one is 9 cm in diame
slavikrds [6]

Answer:

145.8 cm³ of paint

Explanation:

d₁ = Smaller diameter paintball = 5 cm

d₂ = Larger diameter paintball = 9 cm

V₂ = Volume of larger diameter paintball

Volume of smaller diameter paintball

V_1=\frac{4}{3}\pi r_1^3\\\Rightarrow V_1=\frac{4}{3}\pi \left(\frac{d_1}{2}\right)^3\\\Rightarrow V_1=\frac{4}{24}\pi d_1^3

Similarly

V_2=\frac{4}{24}\pi d_2^3

Dividing the above two equations, we get

\frac{V_1}{V_2}=\frac{d_1^3}{d_2^3}\\\Rightarrow V_2=\frac{V_1}{\frac{d_1^3}{d_2^3}}\\\Rightarrow V_2=\frac{28}{\frac{125}{729}}\\\Rightarrow V_2=163.296\ cm^3

∴ The larger one hold 163.296 cm³ of paint

5 0
3 years ago
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