Answer:
time required after impact for a puck is 2.18 seconds
Explanation:
given data
mass = 30 g = 0.03 kg
diameter = 100 mm = 0.1 m
thick = 0.1 mm = 1 ×
m
dynamic viscosity = 1.75 ×
Ns/m²
air temperature = 15°C
to find out
time required after impact for a puck to lose 10%
solution
we know velocity varies here 0 to v
we consider here initial velocity = v
so final velocity = 0.9v
so change in velocity is du = v
and clearance dy = h
and shear stress acting on surface is here express as
= µ 
so
= µ 
............1
put here value
= 1.75× × 
= 0.175 v
and
area between air and puck is given by
Area = 
area = 
area = 7.85 × 
m²
so
force on puck is express as
Force = × area
force = 0.175 v × 7.85 × 
force = 1.374 × v
and now apply newton second law
force = mass × acceleration
- force = 
- 1.374 × v = 
t = 
time = 2.18
so time required after impact for a puck is 2.18 seconds
The article is not found here but surveys are important because they are representative samples of a population.
<h3>What is a survey?</h3>
A survey is a useful tool based on population samples, which is used to make statistical analyses in a given investigation.
Differences in surveys are generally due to small sample sizes, which may lead to errors in the analysis of data.
In conclusion, the article is not found here but surveys are important because they are representative samples of a population.
Learn more about surveys here:
brainly.com/question/13624055
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Answer:
The atoms are aligned in a particular direction
Explanation:
The atoms become aligned in a particular direction in regions called domains, thus resulting in an overall resultant magnetism due to the spin of the electrons.
<span> (26 m/s)(1 rotation/0.62π m) ≈ 13.35 rotations/s that will do pig that'll do</span>
Gravity Gravitational Force of Gravity
