Answer:
6.9m/s
Explanation:
Given parameters:
Acceleration of the object = 4m/s²
Distance = from x; 2m to x; 8m
Unknown:
Average velocity = ?
Solution:
From the given parameters, we use the right motion equation to solve the problem.
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance covered
Distance = 8m - 2m = 6m
Initial velocity = 0m/s
The final velocity gives us the average velocity in this problem;
v² = 0² + (2 x 4 x 6) = 48
v = √48 = 6.9m/s
<span>Work is required to pull a nucleon out of an atomic nucleus. It has more mass outside the nucleus.</span>
Answer:
θ = cos^(-1) (-A/B)
Explanation:
The image of the reauktant forces A & B are missing, so i have attached it.
Now, from the attached image, we will see that;
Angle between A and B is θ
Also;
A = Bcos(180° − θ)
Now, in trigonometry, we know that;
cos(180° − θ) = -cosθ
Thus;
A = -Bcosθ
cosθ = -A/B
Thus;
θ = cos^(-1) (-A/B)
The answer would be A.Transverse
