Answer:
higher
Explanation:
If it contains a impurity that is insoluble it won't dissolve completely, the solution would be smaller than it is supposed to be, when compared to a compound without such insoluble impurity. Molecular weight determination won't be accurate because the molecular weight obtained will be higher as a result of the fact that the mass of the solute would include the actual solute that is changing the temperature and the excess mass of the impurity.
To solve the concentration, it is equal to the mass of the calcium ions divided by the total mass of the solution.
C = mass of ions / mass solution
C = ( 8.5 x 10 ^-3 g ) / 490 g
C = 1.7 x 10^-5
since the choices are in ppm, multiply it by 10^6
C = (1.7 x 10^-5 ) 10^6
C = 17 ppm
Answer:
a) 40 %
b) 
c) 
Explanation:
For a) we will have to calculate the <u>molar mass</u> of
, so the first step is to find the <u>atomic mass</u> of each atom and multiply by the <u>amount of atoms</u> in the molecule.
C => 12*(6) = 72
H => 1*(12) = 12
O => 6*(16) = 96
Molar mass = 180 g/mol
Then we can calculate the percentage by mass:

For b) we have to start with the <u>reaction of glucose</u>:

Then we have to convert the grams of glucose to moles, the moles of glucose to moles of carbon dioxide and finally the moles of carbon dioxide to grams. To do this we have to take into account the<u> following conversion ratios</u>:
-) 180 g of glucose = 1 mol glucose
-) 1 mol glucose = 6 mol carbon dioxide
-) 1 mol carbon dioxide = 44 g carbon dioxide

For C, we have to start with the conversion from grams of glucose to moles, the moles of glucose to moles of oxygen and finally the moles of oxygen to molecules. To do this we have to take into account the <u>following conversion ratios</u>:
-) 180 g of glucose = 1 mol glucose
-) 1 mol glucose = 6 mol oxygen
-) 1 mol oxygen = 6.023x10^23 molecules of O2

Answer:
KHC₈H₄O₄ + NaOH → KC₈H₄O₄⁻ + Na⁺ + H₂O
Explanation:
Potassium hydrogen phthalate is an acidic salt that is used as a primary standard for acid-base titrations.
In the titration of KHP with NaOH, the salt loses a H⁺ producing water and Na⁺. The reaction is:
KHC₈H₄O₄ + NaOH → KC₈H₄O₄⁻ + Na⁺ + H₂O
I hope it helps!
D. is the same in each compound that an element forms
Hope it helps:)