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evablogger [386]
3 years ago
5

According to Le Châtelier's principle, a system at equilibrium will respond to a stress by shifting in the direction that reliev

es the stress. Chemical reactions can be displaced from their equilibrium positions not only by adding or removing reactants or products but also by changing the volume or temperature. Changes in volume affect the value of the reaction quotient, Q, whereas temperature changes affect the value of the equilibrium constant, K.
Chemistry
1 answer:
Romashka [77]3 years ago
3 0

Answer:

a. reduces the stress

Explanation:

You might be interested in
Would the calculated molar mass be higher, lower, or the same as the actual molar mass of the compound if the unknown contained
Delicious77 [7]

Answer:

higher

Explanation:

If it contains a impurity that is insoluble it won't dissolve completely, the solution would be smaller than it is supposed to be, when compared to a compound without such insoluble impurity. Molecular weight determination won't be accurate because the molecular weight obtained will be higher as a result of the fact that the mass of the solute would include the actual solute that is changing the temperature and the excess mass of the impurity.

3 0
2 years ago
An aqueous solution has a mass of 490 grams containing 8.5 × 10-3 gram of calcium ions. The concentration of calcium ions in thi
sammy [17]
To solve the concentration, it is equal to the mass of the calcium ions divided by the total mass of the solution.
C = mass of ions / mass solution
C = ( 8.5 x 10 ^-3 g ) / 490 g
C = 1.7 x 10^-5
since the choices are in ppm, multiply it by 10^6
C = (1.7 x 10^-5 ) 10^6
C = 17 ppm
5 0
3 years ago
Glucose (C6H12O6) is a key nutrient for generating chemical potential energy in biological systems. We were provided 16.55 g of
harina [27]

Answer:

a) 40 %

b) 4.04~g~CO_2

c) 5.53x10^2^3~molecules~of~O_2

Explanation:

For a) we will have to calculate the <u>molar mass</u> of C_6H_1_2O_6, so the first step is to find the <u>atomic mass</u> of each atom and multiply by the <u>amount of atoms</u> in the molecule.

C => 12*(6) = 72

H => 1*(12) = 12

O => 6*(16) = 96

Molar mass = 180 g/mol

Then we can calculate the percentage by mass:

Percentage~=~\frac{72}{180}*100=40

For b) we have to start with the <u>reaction of glucose</u>:

C_6H_1_2O_6~+~6O_2~->~6CO_2~+~6H_2O

Then we have to convert the grams of glucose to moles, the moles of glucose to moles of carbon dioxide and finally the moles of carbon dioxide to grams. To do this we have to take into account the<u> following conversion ratios</u>:

-) 180 g of glucose = 1 mol glucose

-) 1 mol glucose = 6 mol carbon dioxide

-) 1 mol carbon dioxide = 44 g carbon dioxide

16.55~g~C_6H_1_2O_6\frac{1~mol~C_6H_1_2O_6}{180~g~C_6H_1_2O_6}\frac{6~mol~CO_2}{1~mol~C_6H_1_2O_6}\frac{44~g~CO_2}{1~mol~CO_2}=4.04~g~CO_2

For C, we have to start with the conversion from grams of glucose to moles, the moles of glucose to moles of oxygen and finally the moles of oxygen to molecules. To do this we have to take into account the <u>following conversion ratios</u>:

-) 180 g of glucose = 1 mol glucose

-) 1 mol glucose = 6 mol oxygen

-) 1 mol oxygen = 6.023x10^23 molecules of O2

16.55~g~C_6H_1_2O_6\frac{1~mol~C_6H_1_2O_6}{180~g~C_6H_1_2O_6}\frac{6~mol~O_2}{1~mol~C_6H_1_2O_6}\frac{6.023x10^2^3~molecules~O_2}{1~mol~O_2}=~5.53x10^2^3~molecules~of~O_2

4 0
3 years ago
Write the acid-base reaction that occurred in the titration of potassium hydrogen phthalate(KHP), KHC8H4O4with sodium hydroxide,
ExtremeBDS [4]

Answer:

KHC₈H₄O₄ + NaOH → KC₈H₄O₄⁻ + Na⁺ + H₂O

Explanation:

Potassium hydrogen phthalate is an acidic salt that is used as a primary standard for acid-base titrations.

In the titration of KHP with NaOH, the salt loses a H⁺ producing water and Na⁺. The reaction is:

KHC₈H₄O₄ + NaOH → KC₈H₄O₄⁻ + Na⁺ + H₂O

I hope it helps!

8 0
3 years ago
An oxidation number
melamori03 [73]
D. is the same in each compound that an element forms
Hope it helps:)
5 0
3 years ago
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