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alexgriva [62]
3 years ago
11

What is the Damkohler number? b) What is the significance of a system with a low Damkohler number?

Chemistry
1 answer:
elena-s [515]3 years ago
8 0

Explanation:

(a)  A number which is dimensionless and provides us an estimate of the degree of conversion which can be achieved in CSTR, that is, continuous stirred tank reactor is known as Damkohler number.

This number is denoted as Da.

Mathematically,     Da = \frac{\text{reaction rate}}{\text{convection rate}}

             Da = \frac{-rA \times V}{Fa_{o}}

Now, for first order system, Da = \frac{-rA \times V}{Fa_{o}}

                        = \frac{k \times CA_{o} \times V}{v \times CA_{o}} = Tk

where,      rA = rate of reaction

                V = volume of reactor

                Fa_{o} = molar flow rate of component A

                 k = rate constant

               CA_{o} = initial concentration of A

                  v = volumetric flow rate of A

                  T = residence time

(b)   Since, from a given Damkohler number we can figure out the possible conversion of CSTR, that is, continuous stirred tank reactor.

So, if we have a low Damkohler number then the system will give us a less conversion formula. As the conversion is as follows.

                       X = \frac{Da}{Da + 1}

Hence, we can conclude that Da \leq 0.1 will give less than 10% conversion as calculated by using above formula.

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Temperature.

Explanation:

Temperature is a measure of the average kinetic energy of a system.

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How many grams of hcl is dissolved in 500 ml of a 0.2 m hcl solution?
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2 years ago
A student placed 18.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
mamaluj [8]

Answer:

1.30464 grams of glucose was present in 100.0 mL of final solution.

Explanation:

Molarity=\frac{moles}{\text{Volume of solution(L)}}

Moles of glucose = \frac{18.5 g}{180 g/mol}=0.1028 mol

Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = \frac{0.1028 mol}{0.1 L}=1.028 mol/L

A 30.0 mL sample of above glucose solution was diluted to 0.500 L:

Molarity of the solution before dilution = M_1=1.208 mol

Volume of the solution taken = V_1=30.0 mL

Molarity of the solution after dilution = M_2

Volume of the solution after dilution= V_2=0.500L = 500 mL

M_1V_1=M_2V_2

M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}

M_2=0.07248 mol/L

Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

0.07248 mol/L=\frac{\text{moles of glucose}}{0.1 L}

Moles of glucose = 0.07248 mol/L\times 0.1 L=0.007248 mol

Mass of 0.007248 moles of glucose :

0.007248 mol × 180 g/mol = 1.30464 grams

1.30464 grams of glucose was present in 100.0 mL of final solution.

4 0
3 years ago
If an alloy is formed that is 50 mol% silver and 50 mol% gold, what is the karat number of the alloy?
Allisa [31]
Answer : 12 karat

Explanation : When pure gold is considered to be 24 karat then if its 50 mol% silver and 50 mol% silver then using karat scale calculation;

Karat/24 X 100 = 50 mol% (for gold) in alloy

So, Karat = (50 X 24) / 100 = 12 karat.

Hence the alloy will be of 12 karat.
7 0
3 years ago
Read 2 more answers
What is the molarity if 2.00 liters containing 49.0 grams of sodium carbonate [Na2CO3)?
yKpoI14uk [10]

Answer: The molarity of solution is 0.231 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Molar mass of Na_2CO_3 = 2\times 22.99+1\times 12.01+3\times 16.00=105.99

moles of Na_2CO_3 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{49.0g}{105.99g/mol}=0.462mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.462mol}{2.00L}

Molarity=0.231M

Therefore, the molarity of solution is 0.231 M

5 0
3 years ago
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