How many grams are needed to obtain 1.5 moles of mgco3?
2 answers:
Molar mass MgCO3 => 84.31 g/mol
1 mole MgCO3 ----------- 84.31 g
1.5 moles MgCO3-------- ??
1.5 x 84.31 / 1 => 126.465 g
126 g
Explanation:
A mole of a substance is the ratio of the mass of the substance to its molar mass.
Molar mass of a molecule is the sum of the atomic mass of the individual elements.
Molar mass of MgCO₃ = 24 + 12 + (16 x 3) = 84 g/mol
Given,
Moles = 1.5
Moles = mass / molar mass
Mass = moles x molar mass = 1.5 mol x 84 g/mol = 126 g
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