How many moles are in 33 grams of Boron (B)?

Chemistry

1 answer:

azamat2 years ago

7 0

Answer:

2.77495 moles

Explanation:

Boron= 10.811g (according to periodic table)

$33g*\frac{1mole}{10.811g B}=2.774951 moles B$

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The question is incomplete, here is the complete question:

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Explanation:

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