3 years ago

What is 11/12 minus 7/9

Mathematics

2 answers:

Bezzdna [24]3 years ago

8 0

Answer:

5/36

Step-by-step explanation:

This is in fractions so that's what i did and its simplified as well

Shtirlitz [24]3 years ago

6 0

The answer is: 5/36.

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What value of b makes the polynomial below a perfect square? x2 - bx 36

Svetlanka [38]

B = -12

x^2 + 12x + 36
(x+6)(x+6)

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3 years ago

Here's a graph of a linear function. Write the equation that describes that function

kifflom [539]

Y = 2/3x + 3 is the answer

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3 years ago

What is the value of a for the exponential function in the graph represented in the form of f(x)=a(b^x)

Rina8888 [55]

Note: The complete question, along with the graph, is attached below.

Answer:

The value of a = 3

Step-by-step explanation:

Given the function

$f\left(x\right)=a\left(b^x\right)$

From the attached graph, it is clear that

at x = 0,

$f\left(0\right)=a\left(b^0\right)$

$\:f\left(0\right)\:=\:a\:\times \:1$ ∵ $b^0=1$

$f\left(0\right)=a$

Thus

When x = 0, the y-intercept will be:

$f\left(0\right)=a$

From the attached figure, it is clear that

at x = 0, the value of y = 3

putting y = 3 in the equation

$f\left(0\right)=a$

3 = a ∵ $f\left(0\right)=y=3$

Therefore, the value of a = 3

6 0

3 years ago

Jane walks 5 meters east, then 12 meters north.

anzhelika [568]

43 degrees is her displacement

7 0

3 years ago

a reduced fat cookie contains 11g of fat per serving. in order for food to be termed 'reduced fat', it must have at least 20% le

Svetllana [295]

Personally, I did this in a kinda weird way but I think that it should be correct

-How I figured the answer out-

I took 11g and wrote 80% next to it, because after all it has 80% less fat than the regular cookie.

Then, I scaled it down to 10% by dividing by 8, which got me

1.375g = 10%

And finally, I multiplied by 10 to now have 100% (meaning, a regular serving size cookie) and be left with the result: 13.75g

-The answer-

13.75g (don't forget to write the units)

Have a great day :)

6 0

3 years ago