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3 years ago

5

Jace invested $65,000 in an account paying an interest rate of 2.5% compounded continuously. Assuming no deposits or withdrawals

are made, how long would it take, to the nearest year, for the value of the account to reach $93,400?

1 answer:

Tomtit [17]3 years ago

7 0

Answer:

15 years

Step-by-step explanation:

93400=65000*e^(.025x)

x=14.5 which rounds to 15

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In analyzing hits by certain bombs in a war, an area was partitioned into 553 regions, each with an area of 0.95 km2. A total

Leto [7]

Answer:

Probability of having two hits in the same region = 0.178

mu: average number of hits per region

x: number of hits

e: mathematical constant approximately equal to 2.71828.

Step-by-step explanation:

We can describe the probability of k events with the Poisson distribution, expressed as:

$P(x=k)=\frac{\mu^ke^{-\mu}}{k!}$

Being μ the expected rate of events.

If 535 bombs hit 553 regions, the expected rate of bombs per region (the events for this question) is:

$\mu=\frac{\#bombs}{\#regions} =\frac{535}{553}= 0.9674$

For a region to being hit by two bombs, it has a probability of:

$P(x=2)=\frac{\mu^2e^{-\mu}}{2!}=\frac{0.9674^2e^{-0.9674}}{2!}=\frac{0.9359*0.38}{2}=0.178$

4 0

3 years ago

All together, 3 people have 120 coins. mark has 3 times as many as joel, and joel has 1/2 as many as sandra. how many coins does

oksano4ka [1.4K]

Joel = j, Mark = m, Sandra = s
j + m + s = 120
m = 3j
j = 1/2 s --> s = 2j
plug in (substitute) each letter to make it in terms of only j: j + m + s = 120
j + 3j + 2j = 120
6j = 120
6j/6 = 120/6
j = 20
now plug in for the j & s equation:
s = 2j = 2(20) = 40
Therefore Sandra has 40 coins!

7 0

3 years ago

suppose the theoretical probability of winning a prize in the carnival game 0.18 based on this probability how many more custome

Harlamova29_29 [7]

The number of customers I would have expected to win the prize is 6.

<h3>How many more customers would I have expected to win the prize?</h3>

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

Based on the probability, the number of customers I would have expected to win: 0.18 x 300 = 36

How many more people I would have expected to win : 36 - 30 = 6

Please find attached the complete question. To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

6 0

2 years ago

Sheldon harvests the strawberries and tomatoes in his garden. He picks 1 2/5 kg less strawberries in the morning than in the aft

Natalija [7]

Let

x ----> kilograms of strawberries that Sheldon picks in the morning

y ---> kilograms of strawberries that Sheldon picks in the afternoon

so

we have that

x=y-1 2/5

x=2 1/4 kg

substitute

2 1/4=y-1 2/5

Convert mixed numbers to an improper fraction

1 2/5=1+2/5=7/5

2 1/4=2+1/4=9/4

substitute

9/4=y-7/5

y=(9/4)+(7/5)

y=(45+28)/20

y=73/20 kg

Adds kilograms in the morning and afternoon

x+y=(9/4)+73/20)

x+y=(45/20)+(73/20)

x+y=118/20 kg

Convert to mixed number

118/20=100/20+18/20=5+18/20=5+9/10=5 9/10 kg

therefore

<h2>The answer is 5 9/10 kg</h2>

3 0

1 year ago

Suppose both the mean and the median of a distribution are 6. which of these statements is true about the mode of the distributi

PolarNik [594]

A) this is not enough information to compare the mode.

For example:

{1,1,6,11,11]: mean 6, median 6, mode 1 and 11

{4,4,6,8,8} mean 6, median 6 mode, mode 4 and 8

8 0

3 years ago