Solve the volume formula V=lwh for h

Mathematics

1 answer:

MAXImum [283]3 years ago

4 0

V/LW=H , you have to isolate the h so you must divide both sides by LW

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An astronaut visited mars. his weight on earth was 180 pounds, and his weight on mars was only 72 pounds. he removed a rock with

Anton [14]

The question given above may be answered through the concept of ratio and proportion. The ratio of the man's weight on Earth and Mars should be equal to the ratio of the rock's weight on Earth and Mars. By letting x be the rock's mas on Earth, the equation that would best represent the situation is,
180 / 72 = x / 16
The value of x is equal to 40. Thus, the rock weighs 40 pounds on Earth.

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2 years ago

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What problem do you set up to find x and y

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You can use y=mx+b or x-1x/y-1y

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Slav-nsk [51]

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Answer:

$\angle A =\angle B =90^\circ$

Step-by-step explanation:

The diagram of the sled kite is attached below.

The central part of the kite is square.

We know by the property of a square that all its angles are congruent and equal to 90 degrees.

Therefore:

$\angle A =\angle B =90^\circ$

Angles A and B are congruent.

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3 years ago

Which of the following best describes a regular tessellation?A. A tessellation that uses only one type of regular polygonB. A te

Naya [18.7K]

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Step-by-step explanation:

When we cover a surface with a pattern of a flat geometric shapes such that there should have no overlaps or gaps, then the surface is called a tessellation.

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Hence, A is the correct option.

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2 years ago

I’m still stuck on this

kicyunya [14]

Using the frequency table, you can roughly imagine the how the histogram/graph of the values will look in your head. The closer you are to 0, the higher the frequencies, so the higher bars that you graph. As you get further away, the frequencies get smaller, so the bars you graph will also be shorter. The graph will look something similar to middle graph in the picture I attached.

So now its time to match the look of the graph to the types of distributions you have. It's clearly not uniform/bell-shaped (those are the same thing) because its not symmetrical like the graph on the left in the picture I attached. It's not left-skewed like the graph on the right because our graph is higher on the left. That leaves right-skewed as the correct answer.

In right-skewed distributions, the mean<span> is typically greater than the median. You also could have tackled the problem by finding the mean and the median, but the way above is faster.</span>

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3 years ago