1) cscΘ = - 2
=>
1
------ = - 2
sinΘ
=> sinΘ = - 0.5 => Θ is in the third and fourth quadrant
=> Θ = 180° + 30° = 210°
and Θ = 360° + 30° = 330°
2) tan Θ = √3
=> Θ = 60° and Θ = 180° + 60° = 240°
Answer:
b. 82m³
Step-by-step explanation:

Answer:
f⁻¹(x) = (1/2)x +5
Step-by-step explanation:
In y = f(x), swap the variables, then solve for y. The expression you get is f⁻¹(x).
... y = 2x -10
... x = 2y -10 . . . . . . swapped variables
... x +10 = 2y . . . . . add 10
... (1/2)x + 5 = y . . . . divide by 2
... f⁻¹(x) = (1/2)x + 5 . . . . . . rewrite using function notation
sdfsdf
4) 
Multiply by 2 on both sides
3m + 15 = 45
Subtract both sides by 15
3m = 30
Divide both sides by 3
so m = 3
5) 
Multiply both sides by 8
168 = q + 35
Subtract both sides by 35
q = 133
6) 
Subtract 14 from both sides

multiply by -11 on both sides
4x = 572
Divide both sides by 4
x= 143
7) 
Add 6 on both sides

Multiply both sides by 5
3c = 75
Divide both sides by 3
c = 25
8) 
Subtract both sides by 17

Multiply both sides by -2
t = -52
9) 
Multiply both sides by -7
42= 5p + 2
subtract 2 from both sides
40 = 5p
Divide both sides by 5
so p = 8