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3 years ago

A high speed train in japan travels a distance of 300 km in 3.60x10^3 seconds . What is the average speed of this train

Physics

1 answer:

Bezzdna [24]3 years ago

8 0

83.33km per second.

Speed = distance ÷ time.

Speed = 300 ÷ 3.60000

Speed = 83.33km per second

hope that helps.

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a ball is thrown vertically upward with an initial speed of 40 m/s. how high is the ball above the ground when it stops

NISA [10]

Answer:

80m, assuming g=10m/s^2

Explanation:

40m/s will be reduced to 0m/s in 4 seconds. 4 seconds x 40m/s would be 160m up, but you will only get half of that because you decelerate linearly to 0m/s. This leaves you with 4 x 20 = 80m.

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3 years ago

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lianna [129]

Answer:

So coefficient of kinetic friction will be equal to 0.4081

Explanation:

We have given mass of the block m = 0.5 kg

The spring is compressed by length x = 0.2 m

Spring constant of the sprig k = 100 N/m

Blocks moves a horizontal distance of s = 1 m

Work done in stretching the spring is equal to $W=\frac{1}{2}kx^2=\frac{1}{2}\times 100\times 0.2^2=2J$

This energy will be equal to kinetic energy of the block

And this kinetic energy must be equal to work done by the frictional force

So $\mu mg\times s=2$

$\mu\times 0.5\times 9.8\times 1=2$

$\mu =0.4081$

So coefficient of kinetic friction will be equal to 0.4081

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3 years ago

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andre [41]

Answer:

0.035 N

Explanation:

Parameters given:

Charge q1 = -3.31x10^(-7) C

Charge q2 = -5.7x10^(-7) C.

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F = (k* q1 * q2) / R²

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I don't understand the language.....

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