All categories

3 years ago

A high speed train in japan travels a distance of 300 km in 3.60x10^3 seconds . What is the average speed of this train

Physics

1 answer:

Bezzdna [24]3 years ago

8 0

83.33km per second.

Speed = distance ÷ time.

Speed = 300 ÷ 3.60000

Speed = 83.33km per second

hope that helps.

You might be interested in

At take off a plane flies 100 km north before turning east to fly 200 km east. How far is its destination from where the plane t

andrew-mc [135]

First the plane turns 100 km North, and than 200 km East. Since both the directions are perpendicular to each other, therefore we can apply the Pythagoras theorem to calculate the distance between the destination and the point where plane took off

=100^{2}+200^{2}

D=223.60 km=224 km

Therefore, The destination is 224 km from where the plane took off

8 0

3 years ago

What is the displacement of the GBS cross-country team if they begin at the school, run 10 miles, and finish back at the school?

olga2289 [7]

Answer:

Explanation:

8 0

3 years ago

What gives an atom its charge?

s344n2d4d5 [400]

An atom with a neutral charge is one where the number of electrons is equal to the atomic number

hope i helped

5 0

3 years ago

Read 2 more answers

A uniform thin wire is bent into a quarter-circle of radius a = 20.0 cm, and placed in the first quadrant. Determine the coordin

Mashcka [7]

Answer:

$r_{cm}=[12.73,12.73]cm$

Explanation:

The general equation to calculate the center of mass is:

$r_{cm}=1/M*\int\limits {r} \, dm$

Any differential of mass can be calculated as:

$dm = \lambda*a*d\theta$ Where "a" is the radius of the circle and λ is the linear density of the wire.

The linear density is given by:

$\lambda=M/L=M/(a*\pi/2)=\frac{2M}{a\pi}$

So, the differential of mass is:

$dm = \frac{2M}{a\pi}*a*d\theta$

$dm = \frac{2M}{\pi}*d\theta$

Now we proceed to calculate X and Y coordinates of the center of mass separately:

$X_{cm}=1/M*\int\limits^{\pi/2}_0 {a*cos\theta*2M/\pi} \, d\theta$

$Y_{cm}=1/M*\int\limits^{\pi/2}_0 {a*sin\theta*2M/\pi} \, d\theta$

Solving both integrals, we get:

$X_{cm}=2*a/\pi=12.73cm$

$Y_{cm}=2*a/\pi=12.73cm$

Therefore, the position of the center of mass is:

$r_{cm}=[12.73,12.73]cm$

5 0

3 years ago

A radar antenna is tracking a satellite orbiting the earth. At a certain time, the radar screen shows the satellite to be 118 km

ruslelena [56]

Answer:

x component 60.85 m

y component 101.031 m

Explanation:

We have given distance r = 118 km

Angle which makes from ground = 58.9°

(a) X component of distance is given by $r_x=rcos\Theta =118\times cos58.9=118\times 0.5165=118=60.85m$

(b) Y component of distance is given by $r_Y=rcos\Theta =118\times sin58.9=118\times 0.8562=101.0316m$

These are the x and y component of position vector

6 0

3 years ago