To find the relative frequencies, divide each frequency by the total number of throws - in this case, 100.
Red: 10/100=1/10=0.1
Yellow:35/100=0.35
Blue:48/100= 0.48
Misses: 7/100=0.07
The event of landing in the red region has a relative frequency of 0.1 which means the dart landed in the red region about 10% (0.1 x 100%) of the time.
Answer:
Resistance in pencil sharpener = 12 ohms
Explanation:
Given:
Voltage in pencil sharpener = 6 volts
Current in pencil sharpener = 0.5 amps
Find:
Resistance in pencil sharpener
Computation:
Resistance = Voltage / Current
Resistance in pencil sharpener = Voltage in pencil sharpener / Current in pencil sharpener
Resistance in pencil sharpener = 6 / 0.5
Resistance in pencil sharpener = 12 ohms
Answer:
The final temperature is 85.86°C.
Explanation:
Given that,
Mass of tea = 200 g
Mass of glass = 150 g
Initial temperature = 25°C
We need to calculate the final temperature
When equilibrium is reached, assuming no heat flows to the surroundings
So,
![Q_{glass}+Q_{tea}=0](https://tex.z-dn.net/?f=Q_%7Bglass%7D%2BQ_%7Btea%7D%3D0)
![m_{g}C\Delta T+m_{g}C\Delta T=0](https://tex.z-dn.net/?f=m_%7Bg%7DC%5CDelta%20T%2Bm_%7Bg%7DC%5CDelta%20T%3D0)
We know that,
Specific heat of tea = 1.00 cal/gm° C
Specific heat of tea = 0.20 cal/gm° C
Put the value into the formula
![150\times0.20\times(T_{2}-T_{1})+200\times1.00\times(T_{2}-T_{1})](https://tex.z-dn.net/?f=150%5Ctimes0.20%5Ctimes%28T_%7B2%7D-T_%7B1%7D%29%2B200%5Ctimes1.00%5Ctimes%28T_%7B2%7D-T_%7B1%7D%29)
![30T_{2}-30T_{1}+200T_{2}-200T_{1}=0](https://tex.z-dn.net/?f=30T_%7B2%7D-30T_%7B1%7D%2B200T_%7B2%7D-200T_%7B1%7D%3D0)
![30T_{2}+200T_{2}=30T_{1}+200T_{1}](https://tex.z-dn.net/?f=30T_%7B2%7D%2B200T_%7B2%7D%3D30T_%7B1%7D%2B200T_%7B1%7D)
Put the value of initial temperature
![T_{2}=\dfrac{30\times25+200\times95}{230}](https://tex.z-dn.net/?f=T_%7B2%7D%3D%5Cdfrac%7B30%5Ctimes25%2B200%5Ctimes95%7D%7B230%7D)
![T_{2}=85.86^{\circ}C](https://tex.z-dn.net/?f=T_%7B2%7D%3D85.86%5E%7B%5Ccirc%7DC)
Hence, The final temperature is 85.86°C.
G=(G*M)/r²
g-acceleration due the gravity, g=?
G-the universal gravitational constant, G=6.673x10^(-11)N*m²/kg²
M-the mass of the earth, M=5.98x10^(24)kg
r-the radius of the earth, r=6370km=6370000m
g=(6.673x10^(-11)N*m²/kg²)*(5.98x10^(24)kg)/(6370000m)²
g=9.834m/s²