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Musya8 [376]
3 years ago
15

If you need a wet paper towel out on the counter is a vintage I was change of state cuts is this

Physics
1 answer:
coldgirl [10]3 years ago
4 0
As long as green Barghouti on painted charge. (Answer matches logic of the question.)
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Calculate the critical angle for light going from Glycerine to air.
Georgia [21]
The refractive index for glycerine is n_g=1.473, while for air it is n_a = 1.00.

When the light travels from a medium with greater refractive index to a medium with lower refractive index, there is a critical angle over which there is no refraction, but all the light is reflected. This critical angle is given by:
\theta_c = \arcsin ( \frac{n_2}{n_1} )
where n1 and n2 are the refractive indices of the two mediums. If we susbtitute the refractive index of glycerine and air in the formula, we find the critical angle for this case:
\theta_c = \arcsin ( \frac{1.00}{1.473} )=42.8^{\circ}
6 0
3 years ago
Q1. Which statement is correct
marishachu [46]

Answer:

C

D

Explanation:

7 0
3 years ago
• La longitud de un alambre de un sujetador de papel (clip) extendido mide 86 mm. ¿Cuántos sujetadores se pueden obtener de un r
kari74 [83]

Answer:

34883.7

Explanation:

Primero hay que convertir las dos unidades a la misma unidad-cm-

3km- 300000 cm

86mm- 8.6mm

Después hay que dividir

300000/8.6= 34883.7209302 ~ 34883.7

7 0
3 years ago
A normal blood pressure reading is less than 120/80 where both numbers are gauge pressures measured in millimeters of mercury (m
KIM [24]

The pressure value is given by the equation,

P= \rho gh

Where,

\rho represents the density of the liquid

g= gravity

h= Heigth

A) For the measurement of the guage pressure we have the data data,

\rho_{mercury} = 13.6*10^3kg/m^3

h=0.0930m

g=9.8m/s^2

Replacing we get,

P_g=\rho_{mercury}gh

[tex]P_g = (13.6*10^3)(9.8)(0.0930)P_g = 12395Pa[/tex]

In order to find the Absolute pressure, we perform a sum between the atmospheric pressure and that of the Gauge,

B) The atmospheric pressure at sea level is 101325Pa, assuming ideal conditions, we will take this pressure for our calculation, so

P_T = P_a+P_g\\P_T = 101325Pa+12395Pa\\P_T = 113720Pa\\P_T = 113.7kPa

6 0
3 years ago
Can someone help me with these problems? ​
Paladinen [302]
120/60= 2m per s
220/55= 4m per s
720/80= 9m per s
Fastest run: 3rd run
Speed: 9m per s
Slowest: 1st run
Speed: 2m per s

3 0
2 years ago
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