Question

A cell has an internal resistance of 0.02ohms and e.m.f of 2.0v calculate it's terminal p.d if it's delivers (a)5A ( b)50A​

Answer 1

Answer:

(a) The terminal voltage of the cell is 1.9 V.

(b) The terminal voltage of the cell is 1.0 V.

Explanation:

Given:

(a)

E.M.F of the cell (E) = 2.0 V

Internal resistance of the cell (r) = 0.02 ohms

Current passing through the cell (I) = 5 A

Now, the potential difference across the terminals of the cell is given as:

$V=E-Ir$

Plug in the given values and solve for 'V'. This gives,

$V=2.0-(5\times 0.02)\\\\V=2.0-0.1=1.9\ V$

Therefore, the terminal voltage of the cell is 1.9 V.

(b)

E.M.F of the cell (E) = 2.0 V

Internal resistance of the cell (r) = 0.02 ohms

Current passing through the cell (I) = 50 A

Now, the potential difference across the terminals of the cell is given as:

$V=E-Ir$

Plug in the given values and solve for 'V'. This gives,

$V=2.0-(50\times 0.02)\\\\V=2.0-1.0=1.0\ V$

Therefore, the terminal voltage of the cell is 1.0 V.