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lora16 [44]
3 years ago
10

Find two consecutive even integers such that twice the smaller is 16 more than the larger.

Mathematics
1 answer:
qwelly [4]3 years ago
6 0

Answer: smaller: 18 ; larger: 20

Step-by-step explanation:

Let n be the smaller integer. Then the larger integer is n+2. So:

2n=n+2+16

n=18

The smaller integer is 18; the larger one is 20.

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Help ME! I’m literly struggling
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Answer:

See explanation below

Step-by-step explanation:

BD - diagonal                                    Added Construction              

m∠CBD = m∠ADB            Alternate Interior Angles Theorem        

BD ≅ DB                                             Reflexive Property                  

m∠A = m∠C                          Opposite ∠'s Congruent Theorem

ΔABD ≅  ΔCDB                                     AAS or SAS                                    

BC ≅  DA                                                 CPCTC              

AC - diagonal                                             Added Construction    

m∠BCA = m∠CAD                   Alternate Interior Angles Theorem

AC ≅ CA                                                  Reflexive Property    

m∠B = m∠D                              Opposite ∠'s Congruent Theorem

ΔABC ≅  ΔCDA                                            AAS or SAS                                                  

AB ≅  CD                                                           CPCTC          

6 0
3 years ago
Can Someone Help. ?
Elanso [62]

Answer:

6

Step-by-step explanation:

I think its 6 times greater because the length was tripled and the width was doubled thus : 3 * 2 = 6

HOPE THIS HELPED

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