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lora16 [44]
2 years ago
10

Find two consecutive even integers such that twice the smaller is 16 more than the larger.

Mathematics
1 answer:
qwelly [4]2 years ago
6 0

Answer: smaller: 18 ; larger: 20

Step-by-step explanation:

Let n be the smaller integer. Then the larger integer is n+2. So:

2n=n+2+16

n=18

The smaller integer is 18; the larger one is 20.

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Simplify 3 - b (7b + 2) + 3b - (11 - b)​
nirvana33 [79]

Answer: -7b² + 2b - 8

Step-by-step explanation:

<u>Given expression</u>

3 - b (7b + 2) + 3b - (11 - b)

<u>Expand parentheses and apply the distributive property if necessary</u>

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8 0
3 years ago
Question: A box of chocolates contains square chocolates, which weigh 10 g each, and round chocolates, which weigh 8 g each. The
Viktor [21]

Answer: the box contained 9 square chocolates and 15 round chocolates.

Step-by-step explanation:

Let x represent the number of square chocolates contained in the box.

Let y represent the number of round chocolates contained in the box.

The box of chocolates contains square chocolates, which weigh 10g each and round chocolates which weigh 8g each. The combined weight of all the chocolates is 210g. It means that

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y = 2x - 3

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3 years ago
Please answer this! 30 points
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that or dark blue but you have to graph the answer to find where it lands.

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