3 years ago

Find two consecutive even integers such that twice the smaller is 16 more than the larger.

Mathematics

1 answer:

qwelly [4]3 years ago

6 0

Answer: smaller: 18 ; larger: 20

Step-by-step explanation:

Let n be the smaller integer. Then the larger integer is n+2. So:

2n=n+2+16

n=18

The smaller integer is 18; the larger one is 20.

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