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lora16 [44]
3 years ago
10

Find two consecutive even integers such that twice the smaller is 16 more than the larger.

Mathematics
1 answer:
qwelly [4]3 years ago
6 0

Answer: smaller: 18 ; larger: 20

Step-by-step explanation:

Let n be the smaller integer. Then the larger integer is n+2. So:

2n=n+2+16

n=18

The smaller integer is 18; the larger one is 20.

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Evaluate each of the following to three significant figures, and express each answer in SI units using an appropriate prefix: (a
Softa [21]

Answer:

a). 4.86\times 10^{-15} m

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Step-by-step explanation:

In this question we have to convert each option into SI units.

a). 4.86(10^{-6})^{2} mm

= 4.86\times (10^{-12})\times (10^{-3} ) m

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c). (83700)^{2}\times (10^{-3})^{2} N²

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7 0
3 years ago
Whoever gives me the correct answer to this will get a brainlest <br> I need the answer ASAP!
Amiraneli [1.4K]

Volume of cone= 1/3πr^2h

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8 0
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3 0
3 years ago
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