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Levart [38]
3 years ago
13

Find the area of the parallelogram with vertices a(−3, 0), b(−1, 3), c(5, 2), and d(3, −1).

Mathematics
1 answer:
Westkost [7]3 years ago
8 0
 |AD|=(3i-1j)-(-3i-0j)=3i-1j+3i+0j=6i-1j
|BA|=(-3i-0j)-(-1i+3j)=-3i-0j+1i-3j=-2i-3j

Area =|AD|x|BA|
=   i   j    k
    6  -1  0
   -2 -3   0

= -1  0     i        -        6  0    j      +   6 -1   k      
   -3  0                      -2  0               -2 -3           

= 0 i  -   0 j     + (-18-2)k    =   -20 k

√(-20)² =20
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