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lozanna [386]
4 years ago
11

List all the different ways we can use a model to represent things

Chemistry
1 answer:
inn [45]4 years ago
7 0
Modeling for chemistry is periodic table of elements during high school
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9. Determine the number of protons, neutrons, and electrons in one 'H' ion. Explain how you found your
Katyanochek1 [597]

Answer:

'H' ion has only one proton and do not have any electron and neutron.

Explanation:

Hydrogen atom has only one electron and one proton and when it loses that electron, hydrogen ion (H+) is formed which is positively charged (charge of +1) and referred as a proton.

So, hydrogen ion do not left with any electrons or have zero electrons.

Hydrogen (H) atom do not have any neutrons in its tiny nucleus, so hydrogen ion (H+) also do not have neutrons.

Hence, 'H' ion (H+) has only proton and zero electron and neutron.

4 0
3 years ago
A compound contains 14.5 g of magnesium and 3.5 g of oxygen. What is the mass percent of oxygen in the compound?
Helga [31]
80.5%- The total mass of the compound is 18g (14.5 + 3.5) then divide the mass of magnesium by the total. easy way to remember is- (part/whole) x 100
3 0
3 years ago
Read 2 more answers
**ASAP**
Radda [10]

Answer:

b.) methane and long branches alkanes

Explanation:

Petroleum or crude oil is a fossil fuel formed by the decomposition of organisms buried under the earth's surface and subjected to intense pressure and temperature. It is composed of a mixture of hydrocarbons which include paraffins (linear and branched alkanes), naphthenes (cyclic alkanes) and other aromatic compounds.

However, petroleum is predominantly consists of paraffins which have the general formula CnH2n+2 and include methane and other long branched alkanes.

8 0
4 years ago
In most atoms the charges of the protons and electrons cancel each other out and the atom has no what
11111nata11111 [884]
The atom has no charge
7 0
3 years ago
In a sample consisting of 1.00 mol nabr and 0.300 mol ki, what is the mass percent of iodine? (a) 24.9% (b) 32.6% (c) 47.2% (d)
AlexFokin [52]
The quantities you have to know are the molar masses and the molecular stoichiometric ratios. The solution for this problem is as follows:

Mass Percent of Iodine = (Mass of Iodine/Mass of NaBr and KI)*100

Mass of NaBr = 1 mol NaBr * 102.89 g/mol = 102.89 g
Mass of KI = 0.3 mol KI * 166 g/mol = 49.8 g
Mass of KI = 0.3 mol KI * 1 mol I/1mol KI * 1 mol I₂/2 mol I * 253.81 g/mol = 38.07 g

Mass %I₂ = 38.07/(102.89+49.8) * 100 = <em>24.9%</em>
6 0
4 years ago
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