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ANTONII [103]
3 years ago
7

Which of the following conditions on Mars would be the first to kill a human who is unprotected and unassisted by life support?

Chemistry
2 answers:
TiliK225 [7]3 years ago
6 0

Answer:

D

Excess solar radiation due to a missing magnetic field.

Explanation: Solar proton events (SPEs) are bursts of energetic protons accelerated by the Sun. They occur relatively rarely and can produce extremely high radiation levels. Without thick shielding, SPEs are sufficiently strong to cause acute radiation poisoning and death.

Hope this hels

plz mark brainliest

ElenaW [278]3 years ago
5 0

D us answerejeriiriryuyryur

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The pH of a solution is measured as 4.5. What is the hydrogen ion concentration of the solution?
Bond [772]

Answer:

[H⁺] =  3.16 × 10⁻⁵ mol/L

Explanation:

Given data:

pH of solution = 4.5

Hydrogen ion concentration = ?

Solution;

pH = -log [H⁺]

we will rearrange this formula:

[H⁺] =  10∧-pH

[H⁺] = 10⁻⁴°⁵

[H⁺] =  3.16 × 10⁻⁵ mol/L

4 0
3 years ago
A container of N, 03(9) has a pressure of 0.490 atm. When the absolute temperature of the N, O2(g) is tripled, the gas
spayn [35]

Answer: 1.59atm

Explanation:

We have that for the Question "Calculate the final pressure of the gas mixture, assuming that the container volume does not change."

it can be said that

The final pressure of the gas mixture, assuming that the container volume does not change =

From the question we are told

A container of N2O3(g) has a pressure of 0.265 atm. When the absolute temperature of the N2O3(g) is tripled, the gas completely decomposes, producing NO2(g) and NO(g).

3 0
2 years ago
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vagabundo [1.1K]

Answer:

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6 0
3 years ago
True or False: In every gram of sucrose (table sugar) there is 0.513 g of oxygen
Ber [7]

Answer:

True

Explanation:

Step 1: Find molecular formula of sucrose

C₁₂H₂₂O₁₁

Step 2: Convert moles of oxygen present to grams

1 mol O = 16 g O

11 mol O = 176 g O

Step 3: Find molar mass of sucrose

C - 12.01 g/mol

H - 1.01 g/mol

O - 16.00 g/mol

12.01(12) + 22(1.01) + 11(16.00) = 342.34 g/mol C₁₂H₂₂O₁₁

Step 4: Set up dimensional analysis

1 gC_{12}H_{22}O_{11}(\frac{176 gO}{342.34gC_{12}H_{22}O_{11}} )

Step 5: Multiply/Divide and cancel out units

Grams of C₁₂H₂₂O₁₁ and grams of C₁₂H₂₂O₁₁ cancel out.

We are left with grams Oxygen

176/342.34 = 0.514109 grams Oxygen

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3 years ago
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