2×-20/3 =2x help me please

Mathematics

1 answer:

Llana [10]3 years ago

4 0

Answer:

x = - 5

Step-by-step explanation:

Given

$\frac{2x-20}{3}$ = 2x ( multiply both sides by 3 to clear the fraction )

2x - 20 = 6x ( subtract 2x from both sides )

- 20 = 4x ( divide both sides by 4 )

- 5 = x , that is x = - 5

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What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

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EXPLANATION

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The expression given to us is,

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We use the fact that
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${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

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${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

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Method 2: Use indices to solve.

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This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

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${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

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3 years ago

Read 2 more answers

(assume no variable equals 0) PLEASE HELP

saw5 [17]

$(3n^2 + 1) + (8n^2 - 8)\\= 3n^2 + 1 + 8n^2 - 8\\= 11n^2 - 7$