Question

What maximum force do you need to exert on a relaxed spring with a 1.2×104-n/m spring constant to stretch it 6.0 cm from its equilibrium position?

Answer 1

Answer:

Maximum force will be equal to 720 N

Explanation:

We have given that spring constant $k=1.2\times 10^4N/m$

Maximum stretch of the spring x = 6 cm = 0.06 m

We have to find the maximum force on the spring

We know that spring force is given by

$F=kx=1.2\times 10^4\times 0.06=720N$

So the maximum force which is necessary to relaxed the spring will be eqaul to 720 N