The passenger is 2.3 m away from the door after 3 seconds
Since both train and passenger is moving with a constant acceleration so we can use the second equation of motion to calculate the distance cover by train and the passenger,
Distance cover by the train in 3 seconds
S=ut-0.5at^2
S=0*3-0.5*0.6*3^2=2.7 m
Distance cover by passenger in 3 seconds
S=0*3-0.5*1.2*3^2=5.4 m
Now distance of passenger from the train
s=5+2.7-5.4=2.3 m
Therefore after 3 seconds passenger is 2.3 m away from the door.
Answer:
5.865 μs
Explanation:
t₀ = Time taken to decay a muon = 2.20 μs
c = Speed of Light in vacuum = 3×10⁸ m/s
v = Velocity of muon = 0.927 c
t = Lifetime observed
Time dilation
∴Lifetime observed for muons approaching at 0.927 the speed of light is 5.865 μs
note-Unlike the planetary model, our model view is that the electrons move around the nucleus in an electron cloud. Modern atomic theory states that the atom is a diffuse cloud surrounding a small, dense nucleus. Identify which particle is in the nucleus. note-Neutron is a particle in the nucleus.
Answer:
2482 Kg.m/s
Explanation:
Momentum is a product of mass of an object and its velocity with consideration to the direction of velocity and expressed as, p=mv where m represent mass of the ostrich and v is the velocity in m/s, p is momentum.
Substituting the mass of ostrich with 146 kg and the velocity as 17 m/s then the momentum of the ostrich is equal to
P=146*17=2482 kg.m/s
Therefore, the momentum of ostrich is equal to 2482 kg.m/s
Because the force of gravity attracts the comets towards the sun
