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Anna35 [415]
4 years ago
13

What maximum force do you need to exert on a relaxed spring with a 1.2×104-n/m spring constant to stretch it 6.0 cm from its equ

ilibrium position?
Physics
1 answer:
Elena L [17]4 years ago
6 0

Answer:

Maximum force will be equal to 720 N

Explanation:

We have given that spring constant k=1.2\times 10^4N/m

Maximum stretch of the spring x = 6 cm = 0.06 m

We have to find the maximum force on the spring

We know that spring force is given by

F=kx=1.2\times 10^4\times 0.06=720N

So the maximum force which is necessary to relaxed the spring will be eqaul to 720 N

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Intermolecular forces
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A town is considering building a biodiesel power plant that would burn biomass to generate electricity. Which of the following c
zmey [24]

Answer: it reduces dependence on fossil fuels. Disadvantage: it would emit pollution into the air.

3 0
4 years ago
2. Sally put her mug of coffee on the table. The mug has a mass of 1 kg. if the pressure
egoroff_w [7]

We have,

  • The mass of sally's mug is 1 kg
  • The pressure appliedby the mug is 1100 pascal.

We know that,

  • Pressure = Force/Area

As, we already have the value of pressure, let's calculate that of force now;

  • F = ma
  • F = 1 × 9.8 { Acceleration due to gravity, let's round off it to 10}
  • F = 10 N

Just put all the values in the formula now;

  • P = F/A
  • 1100 = 10 / A
  • 1100/10 = A
  • 110 m² = A

As, it is already mention that we need to find the radius of the mug, it is obviously a circular base.

We know that,

  • Surface area = Circumference

So, let's solve it;

  • Circumference = 2πr
  • 110 = 2 × 22/7 × r
  • 110 × 7/2 × 22 = r
  • 5 × 7 = r
  • 35 cm = r

<u>T</u><u>h</u><u>u</u><u>s</u><u>,</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>r</u><u>a</u><u>d</u><u>i</u><u>u</u><u>s</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>c</u><u>i</u><u>r</u><u>c</u><u>l</u><u>e</u><u> </u><u>i</u><u>s</u><u> </u><u>3</u><u>5</u><u> </u><u>c</u><u>m</u><u>.</u>

7 0
3 years ago
A water bug is suspended on the surface of a pond by surface tension (water does not wet the legs). The bug has six leg, and eac
Crazy boy [7]

Answer:

m = 2.2 x 10⁻⁴ kg = 0.22 g

Explanation:

The surface tension of water is 0.072 N/m. So in order for the bug to avoid sinking, its weight per unit length of contact must be no more than the surface tension of water. Therefore,

Weight\ of bug\ per\ unit\ length = Surface\ Tension\ of\ Water\\\frac{mg}{L} = Surface\ Tension\ of Water\\m = \frac{(Surface\ Tension\ of\ Water)(L)}{g}

where,

m = mass of bug = ?

g = acceleration due to gravity = 9.81 m/s²

L = Contact length = (contact length of each leg)(No. of Legs) = (5 mm)(6)

L = 30 mm = 0.03 m

Therefore,

m = \frac{(0.072\ N/m)(0.03\ m)}{9.81\ m/s^{2}} \\

<u>m = 2.2 x 10⁻⁴ kg = 0.22 g</u>

8 0
3 years ago
If an object has a mass of 38 kg, what is its approximate weight on earth?
klasskru [66]
38*10=380 N
To be more exact, 38 should be multiplied by 9.8 instead of 10.
3 0
3 years ago
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