Answer:
11.2Watts
Explanation:
Given parameters:
Energy produced by the engine = 670J
Time taken = 1min = 60s
Unknown:
Number of watts it can output = ?
Solution:
This problem entails finding the power of the engine.
Power is the rate at which work is being done.
So;
Power = 
Power = 
= 11.2Watts
Answer:
elastic partial width is 2.49 eV
Explanation:
given data
ER E = 250 eV
spin J = 0
cross-section magnitude σ = 1300 barns
peak P = 20ev
to find out
elastic partial width W
solution
we know here that
σ = λ²× W / ( E × π × P ) ...................1
put here all value
σ = (0.286)² × W × 
/ ( 250 × π × 20 )
1300 × 
= (0.286)² × W × / ( 250 × π × 20 )
solve it and we get W
W = 249.56 × 
so elastic partial width is 2.49 eV
The work done is given by 742.5 J while the coefficient of kinetic friction between the block and the surface is 0.46.
<h3>What is the work done?</h3>
The work done is given by the use of the formula;
W = F * x
Where;
F = force applied
x = distance covered
W = 150 N * 4.95 m = 742.5 J
Now;
The coefficient of kinetic friction is given by;
μ = F/mg
μ = 150/ 33 * 9.8
μ = 0.46
Learn more about work done:brainly.com/question/13662169
#SPJ1
Answer:
149,916J
Explanation:
Pneumonic device: Kevin is half-mad and very square
this translates to: KE=(1/2)mv^2 !!
KE=(1/2)(78)(62^2)
KE=(39)(3844)
KE=149,916 Joules
Answer: Its in explanation.
Explanation:
Because the electroscope is made from conducting material, some of its electrons move up to the top of the electroscope to be near the charged rod when the rod is held close.
